Question

我正在使用Django 1.6和Django REST Framework。

我有一个非常简单的观点。出于演示目的，我希望它在收到GET请求时返回所有用户的电子邮件地址，并在收到POST请求时返回相同的电子邮件地址。

这是我正在使用的代码：

from rest_framework.views import APIView
from rest_framework.response import Response
from rest_framework import authentication, permissions
from core import models

class ListUsers(APIView):
    def get(self, request, format=None):
        usernames = [user.email for user in models.User.objects.all()]
        return Response(usernames)

    def post(self, request):
        usernames = [user.email for user in models.User.objects.all()]
        return Response(usernames)

当我做GET它工作正常，但是当我做POST时我得到这个错误： No exception message supplied

我无法弄清楚问题是什么，我已经尝试了所有我能想到的东西，我已经搜索过Django REST Framework文档但找不到任何东西。

非常感谢任何帮助。提前谢谢。

更新按要求堆栈跟踪：环境：

Request Method: POST
Request URL: http://localdev:1989/api/rest/v1/register

Django Version: 1.6
Python Version: 2.7.3
Installed Applications:
('django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'rest_framework',
 'core',
 'apiv1')
Installed Middleware:
('django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware')


Traceback:

File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/django/core/handlers/base.py" in get_response
  139.                 response = response.render()
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/django/template/response.py" in render
  105.             self.content = self.rendered_content
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/rest_framework/response.py" in rendered_content
  59.         ret = renderer.render(self.data, media_type, context)
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/rest_framework/renderers.py" in render
  577.         context = self.get_context(data, accepted_media_type, renderer_context)
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/rest_framework/renderers.py" in get_context
  554.             'post_form': self.get_rendered_html_form(view, 'POST', request),
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/rest_framework/renderers.py" in get_rendered_html_form
  423.             data = request.DATA
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/rest_framework/request.py" in DATA
  197.             self._load_data_and_files()
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/rest_framework/request.py" in _load_data_and_files
  267.             self._data, self._files = self._parse()
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/rest_framework/request.py" in _parse
  359.         parsed = parser.parse(stream, media_type, self.parser_context)
File "/usr/local/virtualenvs/wedding/local/lib/python2.7/site-packages/rest_framework/parsers.py" in parse
  63.             raise ParseError('JSON parse error - %s' % six.text_type(exc))

Exception Type: ParseError at /api/rest/v1/register
Exception Value:

我发现它是由提交的错误JSON引起的。例如，如果我有一个额外的逗号。如何使此返回错误消息而不是此500错误？

更新2 POST数据：

{
 "email": "my@email.com",
 "full_name": "mark winterbottom",
 "password": "2secure4u",
}

Answer 1

如果您想要一般错误页面，则应该可以在 urls.py 中设置handler500 url handler。我还注意到你不接受post方法的格式kwarg。你可能想在那里添加它。

另一种可能性是覆盖视图类的dispatch方法并在那里捕获异常，ála：

class ListUsers(APIView):
    def dispatch(self, *args, **kwargs):
        try:
            return super(ListUsers, self).dispatch(*args, **kwargs)
        except ParseError:
            pass
            # Show an error page

    def get(self, request, format=None):
        usernames = [user.email for user in models.User.objects.all()]
        return Response(usernames)

    def post(self, request):
        usernames = [user.email for user in models.User.objects.all()]
        return Response(usernames)

没有提供异常消息（Django REST POST）

1 个答案: