尝试在另一个文件中创建实例时,我收到以下错误。我是PHP的新手,在我的代码中找不到任何语法错误。
致命错误:无法访问第21行/home/leondash/public_html/poll/classes/database.php中的空属性
class Database {
private $host, $username, $password, $database;
private $db;
/** Opens a connection the database */
public function __construct() {
$this->host = "localhost";
$this->username = "dbuser";
$this->password = "dbpass";
$this->database = "dbname";
// the following line is giving the error
$this->db = mysqli_connect($this->host, $this->username, $this->$password, $this->database)
or die('Error: Could not connect to the database');
return true;
}
}
答案 0 :(得分:33)
第21行似乎有错误。更改:
$this->$password
为:
$this->password
修改强>
作为参考,这就是所谓的variable variable。例如:
$a = 'b';
$b = 'I am a variable variable';
echo $$a; // equivalent to `echo $b;` prints 'I am a variable variable'
答案 1 :(得分:1)
他们都是空的。
$this->host = "";
$this->username = "";
$this->password = "";
$this->database = "";
你不能把这个网址称为“”。你不能拥有用户名“”。你不能拥有数据库“”。但可以输入密码“”。不推荐。