Question

我有2个查询，将2个结果复制为：

结果1：

select title1,age1 from tab1 where title1 in ('1','2')

title1 age1 
1       2
2       3

结果2：

select title2,age2 from tab2 where title2 in ('a','c')

title2 age2
a       b
c       d

我希望我的结果可以简单地并排连接在一起作为最终结果：

title1 age1 title2 age2
1       2     a        b
2       3     c        d

如何以简单的方式实现这一目标？我搜索过但没有找到解决方案。

==更新表的架构

+--------+---------+------+-----+---------+-------+
| Field  | Type    | Null | Key | Default | Extra |
+--------+---------+------+-----+---------+-------+
| title1 | int(11) | YES  |     | NULL    |       |
| age1   | int(11) | YES  |     | NULL    |       |
+--------+---------+------+-----+---------+-------+
2 rows in set (0.01 sec)

mysql> describe tab2;
+--------+------------+------+-----+---------+-------+
| Field  | Type       | Null | Key | Default | Extra |
+--------+------------+------+-----+---------+-------+
| title2 | varchar(2) | YES  |     | NULL    |       |
| age2   | varchar(2) | YES  |     | NULL    |       |
+--------+------------+------+-----+---------+-------+

===更新：我试过以下：

select * from 
(select title1, age1 from tab1 order by title1,age1) as result1 , 
(select title2, age2 from tab2 order by title2,age2) as result2 ;

它产生了4行：

+--------+------+--------+------+
| title1 | age1 | title2 | age2 |
+--------+------+--------+------+
|      1 |    2 | a      | b    |
|      2 |    3 | a      | b    |
|      1 |    2 | c      | d    |
|      2 |    3 | c      | d    |
+--------+------+--------+------+

Answer 1

我认为这对你有用。

- 示例

select result1.title1, title1.age1,result2.title2, title2.age2 from 
  (select @i:=@i+1 AS rowId, title1, age1 from tab1,(SELECT @i:=0) a) as result1 , 
  (select @j:=@j+1 AS rowId,title2, age2 from tab2,(SELECT @j:=0) a ) as result2 
where 
  result1.rowId = result2.rowId; 
-- try this it will work perfectly fine

Answer 2

如果没有看到您的SQL查询，很难给出确切的答案，但您应该将它们合并在一起，如下所示：

SELECT  title_1, age_1, title_2, age_2
FROM    table1, table2
WHERE   table1.id = table2.id

Answer 3

select title_1, age_1 from table1
union
select title_2, age_2 from table2

结果是

title_1 age_1 title_2 age_2
1       2     
2       3    
              a        b
              c        d

如何并排加入2个表的结果？

3 个答案: