Question

以下是complex_string，我们希望将其转换为哈希{：stats =＆gt; str1，：search =＆gt; STR2}：

:stats =>  {<%=t('Payment Total($)') %>:&nbsp;&nbsp;<%= number_with_precision(number_with_delimiter(@s_s_results_details.models.joins(:contract => :payments).sum(:paid_amount)), :precision => 2) %>
<%=t('Contract Total($)') %>:&nbsp;&nbsp;<%= number_with_precision(number_with_delimiter(@s_s_results_details.models.joins(:contract).sum(:contract_amount)), :precision => 2) %>},
:search =>  {}

最后，我们想将str1和str2分配给2个变量。我们尝试使用eval(complex_string)并出现错误：

"(eval):1: syntax error, unexpected =>, expecting end-of-input :stats => {<%=t('Payment Tota...          ^"

似乎字符串中的=>会导致错误。有没有办法可以将complex_string转换成哈希？感谢。

Answer 1

这是适用于该特定情况的代码：

complex_string = ":stats =>  {<%=t('Payment Total($)') %>:&nbsp;&nbsp;<%= number_with_precision(number_with_delimiter(@s_s_results_details.models.joins(:contract => :payments).sum(:paid_amount)), :precision => 2) %>
<%=t('Contract Total($)') %>:&nbsp;&nbsp;<%= number_with_precision(number_with_delimiter(@s_s_results_details.models.joins(:contract).sum(:contract_amount)), :precision => 2) %>},
:search =>  {}"

hash = {}
complex_string.scan(/^:(\S+) =>  ({.*?}),?$/m).each do |m|
  hash[m[0].to_sym] = m[1]
end

hash # => {:stats=>"{<%=t('Payment Total($)') %>:&nbsp;&nbsp;<%= number_with_precision(number_with_delimiter(@s_s_results_details.models.joins(:contract => :payments).sum(:paid_amount)), :precision => 2) %>\n<%=t('Contract Total($)') %>:&nbsp;&nbsp;<%= number_with_precision(number_with_delimiter(@s_s_results_details.models.joins(:contract).sum(:contract_amount)), :precision => 2) %>}", :search=>"{}"}

Answer 2

你能在你的控制器中构建它并用json回复吗？

如何在rails 3.2中将复杂的字符串转换为Hash？

2 个答案: