正如我的信息所说,我继承了当地飞镖联盟的统计学家的工作。 (哇哇一个赛季20美元)
我很乐意实施ELO评级系统。
当前数据库表有超过100,000个条目。
有3种不同的游戏。单打,双打和团队。
数据库的发起人输入的游戏如下:
Index Player1_num Player2_num Opp_Player1_num Odd_Player2_num H_team V_team Season Week W L Game_type
两次进入单打比赛。
values(1,20,null,30,null,200,300,11,2,1,0,301_singles)
和
values(2,30,null,20,null,200,300,11,2,0,1,301_singles)
这样做是为了方便个人查看。
双打游戏会有诸如
之类的值(3,20,21,30,31,200,300,11,2,1,0,501_doubles)
(4,21,20,30,31,200,300,11,2,1,0,501_doubles)
(5,30,31,20,21,200,300,11,2,0,1,501_doubles)
(6,31,30,20,21,200,300,11,2,0,1,501_doubles)
再一次,它是为了更容易查询查询各个季节和不同合作伙伴的胜负而构建的。
团队游戏是:
(7,null,null,null,null,200,300,11,2,1,0,team_game)
所以我在表格中添加了一个match_num列,以帮助将游戏归为1个数字。
但是,我不确定如何最好地分配数字,可以理解的是,我不想手动浏览所有90k条目。
注意:早期的季节是手工修改的,并非所有的双重匹配都有4个条目(有些只有1个)。有些匹配也可能不正常(而不是索引:1,2可能是1,9)。
我不知道您是否需要更多信息,我不确定如何发布更大的表格示例。
Current code:
<body>
<?php
include "inc.php";
// Select Max Match Number
$sqlMatch="select max(match_num) from stats_results";
$match =mysql_query($sqlMatch);
$m= $match ? mysql_result($match,0):mysql_error();
$matchno= $m+1; // First Match number
$game=array("'301_singles'","'cricket_singles'","'501_singles'","'301_doubles'","'cricket_doubles'");
// selects max season
$sqlSeason="select max(season_index) from stats_season";
$season =mysql_query($sqlSeason);
$smax= $season ? mysql_result($season,0):mysql_error();
# $smax=2;
// for each season up to max season
for($s=1;$s<=$smax;$s++)
{
// Selects max week within the current season
$sqlWeek="select max(week) from stats_results where season=$s ";
$Week =mysql_query($sqlWeek);
$wmax= $Week ? mysql_result($Week,0):mysql_error();
# $wmax=2;
// for each week within current season up to the max week
for ($w=1;$w<=$wmax;$w++)
{
// each singles game
foreach($game as $g)
{
###########################################################################################################
$result = mysql_query("SELECT * FROM stats_results where season=$s and week=$w and game_code=$g ;") or die(mysql_error());
// Put them in array
for($i = 0; $rows[$i] = mysql_fetch_assoc($result); $i++) ;
// Delete last empty one
array_pop($rows);
//******************************************************
$matches=array();
foreach($rows as $record)
{
// Get a unique match code for this match
$matchid= getMatchID($record);
// Have we seen this ID before? If yes add this record index to the existing array
// otherwise create an array with just this value
if (!isset($matches[$matchid])) $matches[$matchid]= array($record['index_results']); // No
else $matches[$matchid][]= $record['index_results']; // Yes, add this Index
}
// Now $matches is an array of arrays of Index values, grouped by "match" so...
/* Sort $matches by key (see getMatchID for why!) */
ksort($matches);
// Update the table
foreach($matches as $match)
{
// Create SQL instruction to set the match_num for all the Index values in each entry
$sql= "UPDATE stats_results SET match_num = $matchno WHERE index_results IN (".implode(",", $match).")";
echo "<br>";
echo $sql;
/* Execute the SQL using your chosen method! */
// Move the match count on
$matchno++;
}
// End our loops
}
}
}
function getMatchID($gamerecord)
{
$index= "{$gamerecord['season']}-{$gamerecord['week']}-{$gamerecord['game_code']}-";
$players= array(
$gamerecord['player1_num'],
empty($gamerecord['player2_num'])?0:$gamerecord['player2_num'],
$gamerecord['opp_player1_num'],
empty($gamerecord['opp_player2_num'])?0:$gamerecord['opp_player2_num']
);
// Sort the players to get them in a consistent order
sort($players);
// Add the sorted players to the index
$index.= implode('-', $players);
return $index;
}
?>
</body>
答案 0 :(得分:4)
(我把它放到一个答案中,所以我可以让它更好地布局 - 但它并不是真正的“解决方案”!)
我认为我要做的是尝试构建一个按游戏分组的Index
值数组数组 - 然后您可以使用它来创建SQL来更新表。
因此,如果$rows
是所有记录的数组,我们会执行类似以下伪代码的操作:
$matches= array();
foreach($rows as $record)
{
// Get a unique match code for this match
$matchid= getMatchID($record);
// Have we seen this ID before? If yes add this record index to the existing array
// otherwise create an array with just this value
if (!isset($matches[$matchid])) $matches[$matchid]= array($record['Index']); // No
else $matches[$matchid][]= $record['Index']; // Yes, add this Index
}
// Now $matches is an array of arrays of Index values, grouped by "match" so...
/* Sort $matches by key (see getMatchID for why!) */
ksort($matches);
// Update the table
$matchno= 1; // First Match number
foreach($matches as $match)
{
// Create SQL instruction to set the match_num for all the Index values in each entry
$sql= "UPDATE games SET match_num = $matchno WHERE Index IN (".implode(",", $match).")";
/* Execute the SQL using your chosen method! */
// Move the match count on
$matchno++;
}
所有离开的是getMatchID
函数 - 如果我们根据每个匹配的季节,星期以及它的参与者的排序列表(并且首先使用季节和周)给每个匹配一个临时ID,它应该是唯一的对于每个游戏,我们可以稍后按此索引进行排序,以便以正确的顺序获得游戏。所以再次粗略的伪代码,如:
function getMatchID($gamerecord)
{
$index= "{$gamerecord['Season']}-{$gamerecord['Week']}-{$gamerecord['H_Team']}-{$gamerecord['V_Team']}-";
$players= array(
empty($gamerecord['Player1_Num'])?0:$gamerecord['Player1_Num'],
empty($gamerecord['Player2_Num'])?0:$gamerecord['Player2_Num'],
empty($gamerecord['Opp_Player1_Num'])?0:$gamerecord['Opp_Player1_Num'],
empty($gamerecord['Opp_Player2_Num'])?0:$gamerecord['Opp_Player2_Num']
);
// Sort the players to get them in a consistent order
sort($players);
// Add the sorted players to the index
$index.= implode('-', $players);
return $index;
}
所以一切顺利$index
会为你的例子中的第一场单打比赛提供类似11-2-200-300-0-0-20-30
的内容 - 无论我们在哪个比赛记录中查看。
这是否有意义/帮助?