Question

我有以下代码来生成当前日期，以便让我显示今天所采取的步骤数。

但是我想显示之前存储的7天数据，但我不确定如何让日期查询显示过去7天的每一天，以便我可以进行7次查询。我认为有可能将代码写入7次以下，其中-1 -2 -3等等，但我不确定在哪里进行调整以获得先前的日期。

有人可以为我揭开它吗？

// Calculate start of day

- (NSDate * )startDateOfToday
{
    NSCalendar *calendar = [NSCalendar currentCalendar];
    NSDateComponents *components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSDayCalendarUnit
                                               fromDate:[NSDate date]];

    return [calendar dateFromComponents:components];
}

感谢。

Answer 1

您可以简单地将components.day减去要删除的天数。它可以消极。示例代码：

    NSCalendar *calendar = [NSCalendar autoupdatingCurrentCalendar];
    NSDateComponents *components = [calendar components:NSYearCalendarUnit
        | NSMonthCalendarUnit | NSDayCalendarUnit
        fromDate:[NSDate date]];
    for (int i = 0; i < 7; ++i) {
        NSDate *date = [calendar dateFromComponents:components];
        NSLog(@"%d days before today = %@", i, date);
        --components.day;
    }

输出：

2013-12-04 12:37:33.876 7days[62698:303] 0 days before today = 2013-12-04 06:00:00 +0000
2013-12-04 12:37:33.877 7days[62698:303] 1 days before today = 2013-12-03 06:00:00 +0000
2013-12-04 12:37:33.877 7days[62698:303] 2 days before today = 2013-12-02 06:00:00 +0000
2013-12-04 12:37:33.877 7days[62698:303] 3 days before today = 2013-12-01 06:00:00 +0000
2013-12-04 12:37:33.877 7days[62698:303] 4 days before today = 2013-11-30 06:00:00 +0000
2013-12-04 12:37:33.877 7days[62698:303] 5 days before today = 2013-11-29 06:00:00 +0000
2013-12-04 12:37:33.878 7days[62698:303] 6 days before today = 2013-11-28 06:00:00 +0000

iOS和NSDate功能最近7天

1 个答案: