我尝试使用sqlsrv_query从microsoft数据库中获取数据。这是我的代码:
$serverName = "mssql.somee.com\sqlexpress"; //serverName\instanceName
$connectionInfo = array("UID"=>"id","PWD"=>"password","Database"=>"db");
$conn = sqlsrv_connect( "db.mssql.somee.com", $connectionInfo);
if( $conn ) {
echo "Connection established.<br />";
}else{
echo "Connection could not be established.<br />";
die( print_r( sqlsrv_errors(), true));
}
$sql = "select UserName,Email from HTS_User where UserID = 7";
$stmt = sqlsrv_query($conn,$sql);//query is working
if($stmt === false){
die(print_r(sqlsrv_errors(),true));
}else{
echo "sqlsrv_query is working";
echo "<br />";
}
if(sqlsrv_fetch($stmt) ===false){
echo "fetch error";
die(print_r(sqlsrv_errors(),true));
}else{
echo "sqlsrv_fetch is working";
echo "<br />";
}
$n = sqlsrv_get_field($stmt,0);
echo "$n: ";
echo "<br />"
$e = sqlsrv_get_field($stmt,1);
echo "$e: ";
但输出是这而不是真实数据:
资源ID#4: 资源ID#5:
有谁知道这个问题?非常感谢 杰森
答案 0 :(得分:1)
尝试
if(sqlsrv_fetch_array($stmt) ===false){
而不是
if(sqlsrv_fetch($stmt) ===false){
参考: