一直在试用我在php中的新技能来构建一个帐户风格系统,记录收入和付款类似于你在excel中所做的付款。我认为这将是一个很好的起点来测试我的剧照。
现在我已经建立了一个提交到数据库的表单,还有一个页面,允许您查看通过日期记录的付款。
坚持让它显示利润总额。这将根据收到的付款总额减去付款总额来计算。
我已将我的代码附在下面,我真的非常感谢我能得到的任何帮助。
<style>
</style>
<?php
include 'db-connect.php';
$result = mysqli_query($con,"SELECT * FROM payments");
echo "<table border='0' align='center' text-align='left'>
<tr>
<th>Title:</th>
<th>Date:</th>
<th>Incoming:</th>
<th>Outgoing:</th>
<th>Notes:</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['title'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['incoming'] . "</td>";
echo "<td>" . $row['outgoing'] . "</td>";
echo "<td>" . $row['notes'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
添加以下提供的代码后:
<style>
</style>
<?php
include 'db-connect.php';
$result = mysqli_query($con,"SELECT * FROM payments");
$totalIncoming = 0;
$totalOutgoing = 0;
while($row = mysqli_fetch_array($result))
{
$totalIncoming .= $row['incoming'];
$totalOutgoing .= $row['outgoing'];
}
echo "<table border='0' align='center' text-align='left'>
<tr>
<th>Title:</th>
<th>Date:</th>
<th>Incoming:</th>
<th>Outgoing:</th>
<th>Notes:</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['title'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['incoming'] . "</td>";
echo "<td>" . $row['outgoing'] . "</td>";
echo "<td>" . $row['notes'] . "</td>";
echo "</tr>";
}
echo "</table>";
$profit = $totalIncoming - $totalOutgoing;
echo "Profit :".$profit;
mysqli_close($con);
?>
好的,这是对的吗?
<style>
</style>
<?php
include 'db-connect.php';
$result = mysqli_query($con,"SELECT * FROM payments");
$totalIncoming = 0;
$totalOutgoing = 0;
while($row = mysqli_fetch_array($result))
{
$totalIncoming += $row['incoming'];
$totalOutgoing += $row['outgoing'];
echo "<tr>";
echo "<td>" . $row['title'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['incoming'] . "</td>";
echo "<td>" . $row['outgoing'] . "</td>";
echo "<td>" . $row['notes'] . "</td>";
echo "</tr>";
}
echo "</table>";
$profit = $totalIncoming - $totalOutgoing;
echo "Profit :".$profit;
mysqli_close($con);
?>
答案 0 :(得分:2)
试试这个
$totalIncoming = 0;
$totalOutgoing = 0;
while($row = mysqli_fetch_array($result))
{
$totalIncoming += $row['incoming'];
$totalOutgoing += $row['outgoing'];
echo "<tr>";
echo "<td>" . $row['title'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['incoming'] . "</td>";
echo "<td>" . $row['outgoing'] . "</td>";
echo "<td>" . $row['notes'] . "</td>";
echo "</tr>";
}
echo "</table>";
$profit = $totalIncoming - $totalOutgoing;
echo "Profit :".$profit;