代码:
<div id="gallery" data-image="img_folder/g1.jpg"></div>
<div id="gallery" data-image="img_folder/g2.jpg"></div>
<div id="gallery" data-image="img_folder/g3.jpg"></div>
<div id="gallery" data-image="img_folder/g4.jpg"></div>
<div id="gallery" data-image="img_folder/g5.jpg"></div>
CSS:
<style type="text/css">
#gallery { width:100px; height:100px; background-size:cover; }
</style>
jquery:
var el = $("#gallery");
var img = el.attr("data-image");
for(i=0; i<=el.length; i++) {
el.css({ "backgroundImage": "url("+img+")" });
}
但是,图像不显示给div,没有成功任何想法???
答案 0 :(得分:1)
元素的第一个ID必须是唯一的,请使用class
<div class="gallery" data-image="img_folder/g1.jpg"></div>
<div class="gallery" data-image="img_folder/g2.jpg"></div>
<div class="gallery" data-image="img_folder/g3.jpg"></div>
<div class="gallery" data-image="img_folder/g4.jpg"></div>
<div class="gallery" data-image="img_folder/g5.jpg"></div>
和
.gallery { width:100px; height:100px; background-size:cover; }
然后
$('.gallery').css('backgroundImage', function(){
return 'url(' + $(this).data('image') + ')';
})
演示:Fiddle