我以JSON格式启动此RestSharp查询:
var response = restClient.Execute<Report>(request);
我得到的回复包含此数据
[
{
"Columns":
[
{"Name":"CameraGuid","Type":"Guid"},
{"Name":"ArchiveSourceGuid","Type":"Guid"},
{"Name":"StartTime","Type":"DateTime"},
{"Name":"EndTime","Type":"DateTime"},
{"Name":"TimeZone","Type":"String"},
{"Name":"Capabilities","Type":"UInt32"}
],
"Rows":
[
[
"00000001-0000-babe-0000-00408c71be50",
"3782fe37-6748-4d36-b258-49ed6a79cd6d",
"2013-11-27T17:52:00Z",
"2013-11-27T18:20:55.063Z",
"Eastern Standard Time",
2147483647
]
]
}
]
我正在尝试将其反序列化为这组类:
public class Report
{
public List<ReportResult> Results { get; set; }
}
public class ReportResult
{
public List<ColumnField> Columns { get; set; }
public List<RowResult> Rows { get; set; }
}
public class ColumnField
{
public string Name { get; set; }
public string Type { get; set; }
}
public class RowResult
{
public List<string> Elements { get; set; }
}
不幸的是,结果数据为空,我得到了这个例外:
无法将“RestSharp.JsonArray”类型的对象强制转换为类型 'System.Collections.Generic.IDictionary`2 [System.String,System.Object的]'。
我无法弄清楚这里有什么问题。 非常感谢我的帮助。
答案 0 :(得分:22)
试试这个:
var response = restClient.Execute<List<ReportResult>>(request);
修改强>
您还应将ReportResult
更改为:
public class ReportResult
{
public List<ColumnField> Columns { get; set; }
public List<List<string>> Rows { get; set; }
}
你可以摆脱Report
和RowResult
。
答案 1 :(得分:0)
还有另一种创建包装器类的方法:
public class ThirdPartySuggesters : List<ThirdPartySuggester> {}
var response = client.Execute<ThirdPartySuggesters>(request);