我有一个表值函数如下。当我试图同时传递多个参数时,我收到的错误如“函数指定了太多参数”。
CREATE FUNCTION [dbo].[GetCompanyUsers](@CompanyId BIGINT)
RETURNS @Users TABLE (Id BIGINT,Contact NVarchar(4000))
AS
BEGIN
INSERT INTO @Users(Id,Contact)
SELECT [Id]
,ISNULL([FirstName],'')+' ' +ISNULL([LastName],'') AS [Contact]
FROM [dbo].[CompanyAddressesContacts]
WHERE [CompanyId]=@CompanyId
ORDER BY ISNULL([FirstName],'')+' ' +ISNULL([LastName],'')
RETURN
END
我在上面的代码中需要进行哪些修改,以便它允许多个值,我需要在我的数据集中的“WHERE”条件中使用该函数。
WHERE(Document_RFIs.CreatedBy IN
(SELECT Id FROM dbo.GetCompanyUsers(@CompanyId)))
答案 0 :(得分:0)
这可能会有所帮助(但根本问题是 - 除非绝对必要,否则传递逗号分隔字符串是可以避免的 - 这解释了为什么你收到的答案很少): -
--set nocount on
--create table #Document_RFIs (
-- CreatedBy varchar(50),
-- columna varchar(50),
-- columnb varchar(50),
-- columnc varchar(50)
--)
--insert into #Document_RFIs values
-- ('albert einstein','another','value',null),
-- ('marie curie','some',null,'tuna'),
-- ('isaac newton','why','not','provide'),
-- ('kepler','some','test','data'),
-- ('robert boyle','with','your','question'),
-- ('john dalton','it',null,'would'),
-- ('enrico fermi','make','helping','you'),
-- ('peter higgs','so','much','easier')
--create table #CompanyAddressesContacts (
-- companyid int,
-- firstname varchar(50),
-- lastname varchar(50)
--)
--insert into #CompanyAddressesContacts values (22,'albert','einstein')
--insert into #CompanyAddressesContacts values (23,'marie','curie')
--insert into #CompanyAddressesContacts values (23,'isaac','newton')
--insert into #CompanyAddressesContacts values (24,null,'kepler')
--insert into #CompanyAddressesContacts values (25,'robert','boyle')
--insert into #CompanyAddressesContacts values (25,'enrico','fermi')
--insert into #CompanyAddressesContacts values (26,'peter','higgs')
declare @ids varchar(1024)
set @ids='23,24,25'
create table #id (
companyid int
)
declare @pos int
while DATALENGTH(@ids)>0 begin
set @pos=charindex(',',@ids)
if @pos>0 begin
insert into #id values (left(@ids,@pos-1))
set @ids=SUBSTRING(@ids,@pos+1,DATALENGTH(@ids))
end else begin
insert into #id values (@ids)
set @ids=''
end
end
select d.*
from #Document_RFIs d
where exists(
select cac.*
from #CompanyAddressesContacts cac
join #id i on i.companyid=cac.companyid
where isnull(cac.firstname+' ','')+isnull(cac.lastname,'')=d.CreatedBy
)
--drop table #id
--drop table #Document_RFIs
--drop table #CompanyAddressesContacts
答案 1 :(得分:0)
我会做这样的事情:
首先将@CompanyId转换为行
WITH CompanyIds AS (
SELECT Id
FROM CompanyTable -- Same as the source of the @CompanyId
WHERE Id IN (@CompanyId)
)
然后提取所有用户
,Users AS (
SELECT UserId
FROM CompanyIds
CROSS APPLY (
SELECT Id AS UserId
FROM dbo.GetCompanyUsers(CompanyIds.Id)
) AS CA1
)
然后在where语句中使用它
WHERE Document_RFIs.CreatedBy IN (SELECT UserId
FROM Users)