Question

我有以下2组数据，我想将它组合成一整套（总结其中一列）。在此示例中，仅显示了1个项目。

第1集（主表）：

start_date  |item  
2013-10-01  | 1  
2013-10-15  | 1  
2013-10-25  | 1

第2集（详细信息表）：

working_date | item_no | qty  
2013-10-03   |   1     |  2  
2013-10-05   |   1     |  6  
2013-10-18   |   1     |  3  
2013-10-23   |   1     |  4  
2013-10-27   |   1     |  6  
2013-10-28   |   1     |  3

然后，我想根据开始日期将详细信息表中的数据与主表一起分组，并将数量总结如下：

决赛桌（结果）：

starting_date | item_no | total_qty  
2013-10-01    |   1     |   8  
2013-10-15    |   1     |   7  
2013-10-25    |   1     |   9

我很困难的是，我不知道如何在总和数量之前将working_date匹配到starting_date范围来对数量求和。

换句话说，我需要总结从2013-10-01到2013-10-14,2013-10-15到2013-10-24和2013-10-25到2013-10-31的数量

Answer 1

你的问题并不完全清楚，但这应该足以成为你工作的一个例子。

SELECT master_table.starting_date, 
    details_table.item_no, 
    SUM(details_table.qty)
FROM master_table 
JOIN details_table 
  ON master_table.item_no = details_table.item_no
GROUP BY master_table.starting_date, 
         details_table.item_no

Answer 2

declare @startDate Datetime
set @startDate=DATEADD(month,-2,GETDATE()) -- set the startdate 2 months before today
declare @endDate Datetime
set @endDate=GETDATE() -- set the ending date equal to current datetime
declare @DaysStep int
set @DaysStep=10 -- set the step from day to the next day equal to 10 days. 
                -- so if today is 12/01/2013 the next day will be 12/11/2013

declare @results table (starting_date Datetime, item_no int, total_qty int)

while @startDate<@endDate
    begin
        insert into @results
        select starting_date, item_no, sum(qty) as total_qty
        from master as m
        inner join detail as d
        on m.item_no=d.item_no
        where startingDate between @starDate and DATEADD(Days, @DaysStep, @startDate)
    @startDate=DATEADD(Days, @DaysStep, @startDate)
    end

select *
from @results

我想你用的是mssql。否则你应该将上面的代码更改为你的sql方言。您也可以根据需要设置@startDate，@ endDate和@DaysStep。

Answer 3

对于详细信息表中的每个记录，您需要从主表中查找最接近的上一个日期。一旦找到，只需在该日期汇总。

select starting_date, sum(qty)
from (
  select working_date,
         item_no,
         qty,
         (select max(master_table.starting_date)
          from master_table
          where master_table.starting_date <= details_table.working_date
          and master_table.item_no = details_table.item_no
         ) as starting_date
from details_table
  ) as modfied_table
group by starting_date
order by starting_date;

Demo

Answer 4

这对你有用：

SELECT start_date, item_no, sum(qty) as qty 
FROM #mastertable as aa INNER JOIN #detailtable as bb ON aa.item = bb.item_no
WHERE (start_date <= working_date 
    AND working_date < (SELECT TOP 1 start_date FROM #mastertable as innerT WHERE innerT.start_date > aa.start_date))
    OR (working_date >= (SELECT TOP 1 start_date FROM #mastertable as innerT ORDER BY innerT.start_date DESC)
    AND start_date = (SELECT TOP 1 start_date FROM #mastertable as innerT ORDER BY innerT.start_date DESC))
GROUP BY start_date, item_no
ORDER BY start_date

使用相同的密钥将2组数据分组为1组

4 个答案: