这是我的mysql代码和等效的pdo代码我需要知道什么是错的
$id = $_POST['id'];
$query1=mysql_query("SELECT Quantity,id FROM `yumyum`.`food` where `food`.`id` LIKE $id");
$r = array();
while($r = mysql_fetch_assoc($query1)) {
$output = $r['Quantity'];
echo $output;
$query2=mysql_query("UPDATE food SET Quantity = Quantity - 1 where `food`.`id` LIKE ".$r["id"]);
PDO代码
$stmt = $db->prepare("SELECT * FROM yuymuym WHERE id=:id AND Quantity=:Quantity");
$stmt->execute(array($id, $Quantity));
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC)
答案 0 :(得分:-1)
这个怎么样?我不知道$ _POST ['id']是什么,所以你必须自己动手。它更新$ ids数组中id为id的每个项目。因此,这会更新ID为1,2,3,4和5的项目。
$db = new PDO('mysql:host=localhost;dbname=yumyum', 'username_here', 'password_here');
$ids = array(1,2,3,4,5);
foreach($ids as $id){
$stmt = $db->prepare("SELECT Quantity, id FROM `food` WHERE `food`.`id` = :id");
$stmt->bindParam(':id', $id);
$stmt->execute();
$row = $stmt->fetch();
if($row){
//uncomment to see $row content
//var_dump($row);
$rowId = (int)$row['id'];
$rowQuantity = (int)$row['Quantity'];
echo $rowQuantity;
$ustmt = $db->prepare("UPDATE `food` SET `Quantity` = `Quantity` - 1 WHERE `food`.`id` = :id");
$ustmt->bindParam(':id',$rowId);
$ustmt->execute();
}else{
var_dump($stmt->errorInfo());
}
}
但是PDO的基础知识:
查询(使用select,insert,update,其他所有内容):
$id = (int)$_POST['id'];
$else = $_POST['string'];
// Connect to database
$db = new PDO('mysql:host=HOST_HERE;dbname=DATABASENAME_HERE', 'USERNAME_HERE', 'PASSWORD_HERE');
// First we prepare our query
$stmt = $db->prepare("... WHERE `id` = :id AND `something` = :else");
// We bind values to our prepared query
$stmt->bindParam(':id',$id);
$stmt->bindParam(':else',$else);
// We execute our query
$success = $stmt->execute();
// If we want to fetch only one row:
$row = $stmt->fetch();
echo $row['id'];
// If we want to fetch all rows:
$rows = $stmt->fetchAll();
foreach($rows as $row){
echo $row['id'];
}
这些是非常基础的,如果你不明白这里发生了什么,你应该学到更多。