Question

我希望将变量和可数位流解码并解码为二进制字符串，数字， 64个碱基编码字符串。流的最大长度约为21 + 20 = 41位，但可以稍长43,45。

假设位将由某个数组表示。

bits = [1]
encoded = someEncoder(bits)
decoded = someDecoder(encoded)
assert bits == decoded

比特流可以更长，例如：

import random

def generateRandomBits(l):
  bitsBytes = random.getrandbits(l)
  bits = []
  for i in range(l):
    bitsBytes
    bits.append(int(bitsBytes >> i & 1))
  return bits

bits = generateRandomBits(21)
# [0, 1, 1, 1, 0, 0, 1, 0, 0, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1]

考虑它是变量位列表，而编码/解码必须无损：

a = someEncoder([0])
b = someEncoder([0, 0])
assert a != b

Answer 1

要将表示位的整数转换为8位字节（仍为整数），请使用位移：

result = 0
for bit in bits:
    result = result << 1 | bit

或reduce()：

result = reduce(lambda n, b: n << 1 | b, bits)

这可以转换为带有format(result, 'b')的二进制字符串，可选择宽度和0前缀，以零填充到一定长度。

演示：

>>> bits = [0, 1, 1, 1, 0, 0, 1, 0, 0, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1]
>>> reduce(lambda n, b: n << 1 | b, bits)
934809
>>> result = 0
>>> for bit in bits:
...     result = result << 1 | bit
... 
>>> result
934809
>>> format(result, '021b')
'011100100001110011001'

如果您需要直接转到二进制字符串，只需将这些位映射到字符串并加入：

>>> ''.join(map(str, bits))
'011100100001110011001'

可以使用str.zfill()：

将其进一步填充为64个字符

>>> ''.join(map(str, bits)).zfill(64)
'0000000000000000000000000000000000000000000011100100001110011001'

Answer 2

根据@ Martijn的回答，我想你想要以下内容。这使用了对前导零编码的思想来区分前导零的变量长度：

import unittest
import itertools

def encode(bits):
    '''Encode n bits to an integer using a leading 1 to mark the length of the bit stream.

    Example: [0,0,0] == 0b1000 == 16
    '''
    # start with an initial 1.
    # iteratively shift current value left and OR in new bit.
    return reduce(lambda n,b: n << 1 | b,bits,1)

def decode(encoded):
    '''Decode a positive integer into a list of 0/1 values.
    The most significant bit marks the length and is removed.

    Example:  137 = 0b10001001 = [0,0,0,1,0,0,1]
    '''
    if encoded < 1:
        raise ValueError('encoded must be > 0')
    return [1 if c=='1' else 0 for c in format(encoded,'b')][1:]

class Cases(unittest.TestCase):
    def testEncodeZeros(self):
        for i in xrange(100):
            bits = [0]*i
            self.assertEqual(encode(bits),2**i)
    def testEncodeOnes(self):
        for i in xrange(100):
            bits = [1]*i
            self.assertEqual(encode(bits),2**(i+1)-1)
    def testDecodeZeros(self):
        for i in xrange(100):
            encoded = 2**i
            self.assertEqual(decode(encoded),[0]*i)
    def testDecodeOnes(self):
        for i in xrange(100):
            encoded = 2**(i+1)-1
            self.assertEqual(decode(encoded),[1]*i)
    def testEncodeDecode(self):
        for n in xrange(10):
            for bits in itertools.product([0,1],repeat=n):
                self.assertEqual(decode(encode(bits)),list(bits))
    def testDecodeZero(self):
        self.assertRaises(ValueError,decode,0)
    def testDecodeNegative(self):
        self.assertRaises(ValueError,decode,-1)

if __name__ == '__main__':
    unittest.main()

输出：

testDecodeNegative (__main__.Cases) ... ok
testDecodeOnes (__main__.Cases) ... ok
testDecodeZero (__main__.Cases) ... ok
testDecodeZeros (__main__.Cases) ... ok
testEncodeDecode (__main__.Cases) ... ok
testEncodeOnes (__main__.Cases) ... ok
testEncodeZeros (__main__.Cases) ... ok

----------------------------------------------------------------------
Ran 7 tests in 0.041s

OK
>>> encode([0,0,0,0])
16
>>> decode(16)
[0, 0, 0, 0]
>>> encode([])
1
>>> decode(1)
[]
>>> encode([1,0,0,1])
25
>>> decode(25)
[1, 0, 0, 1]
>>> bin(25)
'0b11001'
>>> encode([0,0,0,1,0,0,1])
137
>>> bin(137)
'0b10001001'
>>> decode(137)
[0, 0, 0, 1, 0, 0, 1]

如何在Python中编码位流（不是字节） - 它是什么简单的模块？

2 个答案: