Question

我会清楚地解释一下：我按位置在桌子上有曲棍球统计数据

玩家12：

StatsID  /  PlayerID   / Position  / gamesPlayed / points  /  Season
 1      /     12      /  RW     /      40     /  32     / 2013-2014
 2      /     12     /  Def    /       1     /   1    / 2013-2014

所以我想要一个像这样的查询

Select PlayerID , Season , sum(gamesPlayed) as GP, sum(points) as pts , ???? from
MyPointTable GROUP BY PlayerID, SEASON

我想替换我的????这将使我发挥最重要的位置，所以他像RW一样玩40场比赛。我不能指望，我无法总结。

SQL结果应该给出

ID , Season    , GP , pts, MostPosition
12 , 2013-2014 , 41 , 33 , RW

由于

Answer 1

这适用于PostgreSQL：

SELECT 
    PlayerID AS ID,
    Season,  
    subQuery.sqTotalGames AS GP, 
    subQuery.sqTotalPoints AS pts, 
    position AS MostPosition
FROM
    MyPointTable 
    INNER JOIN
        (
            SELECT 
                PlayerID as sqPlayerID, 
                MAX(gamesPlayed) as sqMaxGames, 
                SUM(gamesPlayed) as sqTotalGames, 
                SUM(points) AS sqTotalPoints 
            FROM 
                MyPointTable 
            GROUP by playerID
        ) subQuery 
            ON subQuery.sqMaxGames = gamesPlayed 
                AND subQuery.sqPlayerID = PlayerID;

Answer 2

它是Sql Server你可以先使用SQL Rank来获得最多的播放然后进行分组

http://technet.microsoft.com/en-us/library/ms176102.aspx

SQL获取来自Group By的最多计数值

2 个答案: