对于我使用XMLUnit 1.5的Java程序,它比较两个XML文件(带有命名空间)。但是,我得到的XPathes不包含任何命名空间。我怎么能告诉XMLUnit todo呢?这可能吗?
这是我的代码:
control = new FileReader(file1);
test = new FileReader(file2);
list = new ArrayList<Unterschied>();
Diff diff;
diff = new Diff(control, test);
diff.overrideElementQualifier(new ElementNameAndAttributeQualifier());
if (diff.similar())
{
MessageDialog.openInformation(null, "Info", "Similar");
}
else if (!diff.similar())
{
DetailedDiff detDiff = new DetailedDiff(diff);
detDiff.overrieElementQualifier(new ElementNameAndAttributeQualifier());
@SuppressWarnings("unchecked")
List<Object> differences = detDiff.getAllDifferences();
for (Object object : differences)
{
Difference difference = (Difference) object;
if (!difference.isRecoverable() && !difference.getDescription().contains("number of child nodes"))
{
controlXPath = difference.getControlNodeDetail().getXpathLocation(); // without Namespaces!
controlValue = difference.getControlNodeDetail().getValue();
testXPath = difference.getTestNodeDetail().getXpathLocation(); // without Namespaces!
testValue = difference.getTestNodeDetail().getValue();
list.add(new Unterschied(controlOrt, controlWert, testOrt, testWert));
}
}
稍后在我的程序中,我评估这些XPathes以获取此节点的正确位置。使用这些位置,我在编辑器中选择适当的文本,以便用户可以看到差异。
我的评估代码:
public void evaluateXPath(String xp, Node node) {
XPath newXPath = new XPathFactoryImpl().newXPath();
XPathExpression xpExp = newXPath.compile(xpath);
NodeList nodeList = (NodeList) xpExp.evaluate(node, XPathConstants.NODESET);
int length = nodeList.getLength();
for (int i=0; i < length; i++) {
IDOMNode iDOMnode = (IDOMNode) nodeList.item(i);
textEditor.selectAndReveal(iDOMnode.getStartOffset(), iDOMnode.getEndOffset()-iDOMnode.getStartOffset());
}
}
感谢您的帮助,抱歉我的英语不好! ;)
答案 0 :(得分:0)
不,XMLUnit 1.x只返回没有任何命名空间指示的普通XPath。
XMLUnit 2.x(正在开发中)将使用可根据NS-URI配置的名称空间的前缀返回XPath。