Question

我有一个由jquery函数触发的动态下拉菜单。我正在显示mysql db的下拉值。之后，我试图从下拉菜单中插入选定的值。我已经能够通过mysqli_成功完成，但在使用PDO时，没有插入任何内容。我仔细检查了变量，没有显示任何错误。如何使用PDO从下拉菜单中插入所选值？ Example

用于创建多个下拉列表的Jquery

<script>
$(document).ready(function () {


$('select').change(function() {
var option = $(this).val();
showFields(option);
return false;
    });


    function showFields(option){ 

        var content = '';
        for (var i = 1; i <= option; i++){
            content += '<div id="course_'+i+'"><label>Course # '+i+'</label><br /><label>Course Name:</label> <select id="coursename_'+i+'" name="coursename_'+i+'"><option value="">--- Select ---</option>"'
                    <?php
                        $course_query = $db_con->prepare("SELECT course_id, course_name FROM courses_selection_list ");
                        $course_query->execute();
                        $data = $course_query->fetchAll();
                        foreach ($data as $row){
                                //dropdown values pulled from database
                           echo 'content += \'<option value="' . $row['course_id'] . ':'.$row['course_name'].'">' . $row['course_name'] . '</option>\';';
                        }

                    ?>
            '"';                   

            content += '</select></br>Class Start Date: <input type="text" id="start_date_'+i+'" name="start_date_'+i+'" class="datepicker" />Class End Date: <input type="text" id="end_date_'+i+'" name="end_date_'+i+'" class="datepicker" /><div>';

        }
        $('#course_catalog').html(content);

    }
});
</script>

PDO插入（不起作用）

<?php
if(isset($_POST['submit'])){
$courses_offered=$_POST['courses_offered'];
$db_con = new PDO($dsn, $user, $password);
for($i=1;$i<=$courses_offered;$i++){
    $course_vals = explode(':',$_POST["coursename_".$i]);
    $acad_id = $_POST['acad_id'];
    $start_date = $_POST["start_date_".$i];
    $end_date = $_POST["end_date_".$i];

    $query_init3 = "INSERT INTO courses_by_academy (academy_id, course_id, course_name, start_date, end_date) VALUES (:acad_id, :course_vals[0],:course_vals[1],:start_date,:end_date);";
    $query_prep3 = $db_con->prepare($query_init3);
    $insert_result3 = $query_prep3->execute(array(
        "acad_id" => $acad_id,
        "course_vals[0]" => $course_vals[0],
        "course_vals[1]" => $course_vals[1],
        "start_date " => $start_date,
        "end_date " => $end_date
    ));
} 
  print_r($_POST);
}
?>

Mysqli插入（工作）

<?php
if(isset($_POST['submit'])){
$courses_offered=$_POST['courses_offered'];
$db_con = new mysqli(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_DATABASE);
    for($i=1;$i<=$courses_offered;$i++)
    {
    $courseVals=explode(':',$_POST["coursename_".$i]);
    $acad_id = $_POST['acad_id'];
    $start_date = $_POST["start_date_".$i];
    $end_date = $_POST["end_date_".$i];

    $db_insert4= $db_con->prepare("INSERT INTO courses_by_academy (academy_id, course_id, course_name, start_date, end_date) VALUES (?,?,?,?,?)");
    $db_insert4->bind_param('issss', $_POST['acad_id'], $courseVals[0], $courseVals[1], $start_date, $end_date);
    $db_insert4->execute();
    }   
 print_r($_POST);
echo  $courseVals;
}
?>

HTML 的

Courses being offered?
<select name="courses_offered">
    <option value="default">---Select---</option>
    <option value="1">1</option>
                </select>
<div id="course_catalog"></div>
<input value="SAVE" name="submit" type="submit">

Answer 1

如上所述，AdRock请根据您的查询绑定您的值。以下是pdo样式中for循环的外观：

if(isset($_POST['submit'])){
$courses_offered=$_POST['courses_offered'];
for($i=1;$i<=$courses_offered;$i++){
    $course_vals = explode(':',$_POST["coursename_".$i]);
    $acad_id = $_POST['acad_id'];
    $start_date = $_POST["start_date_".$i];
    $end_date = $_POST["end_date_".$i];

    $db_insert3= $db_con->prepare("INSERT INTO courses_by_academy (academy_id, course_id, course_name, start_date, end_date) VALUES (?,?,?,?,?)");
    $db_insert3->bindParam(1, $acad_id, PDO::PARAM_INT);
    $db_insert3->bindParam(2, $course_vals[0], PDO::PARAM_INT);
    $db_insert3->bindParam(3, $course_vals[1], PDO::PARAM_INT);
    $db_insert3->bindParam(4, $start_date, PDO::PARAM_STR, 12);
    $db_insert3->bindParam(5, $end_date, PDO::PARAM_STR, 12);
    $db_insert3->execute();

} 
  print_r($_POST);
}

有关使用bindParam的进一步说明，请阅读Manual

下拉列表 - 插入选定的值 - pdo方法无效

1 个答案: