Question

我正在尝试在Codeigniter中创建搜索表单。我想给用户4个不同的搜索选项。对于结果，我想要一个表，显示我正在搜索的表中的所有11列。这是我到目前为止的代码。

控制器：

public function index(){
    $this->searchTest();
}
public function searchTest(){
    $this->load->model('reg_model');

$search_term = array(
    'firstName' => $this->input->post('firstName'),
    'lastName' => $this->input->post('lastName'),
    'street' => $this->input->post('street'),
    'dob' => $this->input->post('dob'));


    $data['query'] = $this->reg_model->test($search_term);


    $this->load->view("reg_header");
    $this->load->view("reg_nav");
    $this->load->view("reg_search_form", $data);
    $this->load->view("reg_search", $data);

型号：

public function test($search_term='default'){



   $this->db->select('*');
   $this->db->from('voterinfo');
   $this->db->like('firstName', $search_term);
   $this->db->or_like('lastName', $search_term);
   $this->db->or_like('street', $search_term);
   $this->db->or_like('dob', $search_term);
   $query = $this->db->get();


   return $query->result_array();

}

查看：

<?php $this->load->library('table'); foreach ($query as $row){ echo $this->table->generate($row); }?>

Answer 1

如果你想使用codeigniter表类放入表，它应该是这样的：

$this->load->library('table');

$this->table->set_heading(array('Name', 'Color', 'Size')); //your column name


foreach($query as $row ){
   $this->table->add_row($row);
}

echo $this->table->generate();

您还需要修改模型。你查询错了，你忘记了密钥，它应该是这样的：

public function test($search_term='default'){



   $this->db->select('*');
   $this->db->from('voterinfo');
   $this->db->like('firstName', $search_term['firstName']);
   $this->db->or_like('lastName', $search_term['lastName']);
   $this->db->or_like('street', $search_term['street']);
   $this->db->or_like('dob', $search_term['dob']);
   $query = $this->db->get();


   return $query->result_array();

}

使用Codeigniter搜索表单

1 个答案: