Question

我正在尝试编写一个字符串或整数公式，它将在括号中查看代码。我的逻辑是这样的：搜索第一个括号，找到最后的括号，并返回其间的所有内容。我确定有一个字符串或整数函数，但不确定哪一个会做的伎俩。顺便说一下，括号之间的代码长度从3到9不等。请检查此代码在此输入代码

var n;
var $;
var str = document.getElementById("demo").innerHTML;
var p = str.indexOf(")");
var q = str.indexOf("(");
var res = str.replace(")", "");
var re = str.replace("(", "");
document.getElementById("demo").innerHTML = res;
var k = str.replace("$", "(" + "$")
           .replace(/,$/, ".")
           .replace(")", "(" + res + ")")
           .replace("(", "(" + res + ")")
           .replace(/O/g, 0)
           .replace(/o/g, 0)
           .replace(/g/g, 9)
           .replace(/\s/g, "");
document.getElementById("demo3").innerHTML = k;

Answer 1

从我对你的问题的理解，你只想搜索一串任何东西，并拉出被paranthesis包围的字符。这很容易。

var foo = 'blah(capture this)blah';

var result = foo.match(/\(([^()]+)\)/);
//this simply says: capture any characters surrounded by paranthesis, as long as there is at least one character.

console.log(result[1]);

根据您的评论进行更新：

逻辑非常容易理解。

var regex = new RegExp(
  '\\(?'+ //optional (
  '\\$?'+ //optional $
  '(\\d+)' //capture any digit, at least one
);

function format(userInput) {
  var results = userInput.match(regex);
  if (results === null) { results = [0,0]; }
  //get the important part (the digits), format it however you want.
  var formatted = '($'+results[1]+'.00)';
  return formatted;
}

//all output ($1234.00)
console.log(format('$1234)'));
console.log(format('($1234.00'));
console.log(format('1234'));
console.log(format('1234.0'));
console.log(format('1234)'));
console.log(format('(1234.0'));

用（）标记替换括号开始和结束标记

1 个答案:

根据您的评论进行更新：