如何在tableview部分标题中实现复选框。我的代码是,
-(UIView *)tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section
{
UIView *tempView=[[UIView alloc]initWithFrame:CGRectMake(0,200,300,244)];
tempView.backgroundColor=[UIColor clearColor];
UIButton *leftSecCheckBtn = [UIButton buttonWithType:UIButtonTypeCustom];
[leftSecCheckBtn setBackgroundImage:[UIImage imageNamed:@"checkbox_empty.png"] forState:UIControlStateNormal];
[leftSecCheckBtn setBackgroundImage:[UIImage imageNamed:@"checkmark_Tick.png"] forState:UIControlStateSelected];
[leftSecCheckBtn setFrame:CGRectMake(22,-2, 26, 26)];
[leftSecCheckBtn addTarget:self
action:@selector(leftSectionCheckBox:)
forControlEvents:UIControlEventTouchUpInside];
[tempView addSubview:leftSecCheckBtn];
}
-(void)leftSectionCheckBox:(id)sender
{
UIButton *selectedButton = (UIButton *) sender;
{
if([selectedButton isSelected ]==YES)
{
[selectedButton setSelected:NO];
}
else
{
[selectedButton setSelected:YES];
}
}
}
在ViewForHeader功能中添加了按钮,但是,按钮的图像没有变化,??
答案 0 :(得分:0)
我认为这可能有所帮助:
-(void)leftSectionCheckBox:(UIButton *)sender {
sender.selected = !sender.isSelected;
if([selectedButton isSelected ]==YES) [selectedButton setSelected:NO];
else [selectedButton setSelected:YES];
}
或者你可以这样做:
-(void)leftSectionCheckBox:(id)sender {
for (UIButton * selectedButton in [[tableView headerViewForSection:0]subviews]) {
if ([selectedButton isKindOfClass:[UIButton class]]) {
if([selectedButton isSelected ]==YES) [selectedButton setSelected:NO];
else [selectedButton setSelected:YES];
}
}}
答案 1 :(得分:0)
试试这个
-(void)leftSectionCheckBox:(id)sender
{
UIButton *selectedButton = (UIButton *) sender;
if([selectedButton isSelected ]==YES)
{
[selectedButton setSelected:NO];
[leftSecCheckBtn setBackgroundImage:[UIImage imageNamed:@"checkbox_empty.png"] forState:UIControlStateNormal];
}
else
{
[selectedButton setSelected:YES];
[leftSecCheckBtn setBackgroundImage:[UIImage imageNamed:@"checkmark_Tick.png"] forState:UIControlStateNormal];
}
}
我更新了答案。否则你必须通过界面构建器来完成。
答案 2 :(得分:0)
设置您的tempView
用户互动功能,
[tempView setUserInteractionEnabled:YES];
你可以最小化你的方法,
-(void)leftSectionCheckBox:(UIButton *)selectedButton
{
selectedButton.selected = !selectedButton.selected;
}