我正在我的项目中实现时间选择器对话框。它不应该选择与当前时间相关的过去值。我的意思是设定采摘的最短和最长时间。
以下是我所做的时间戳的过程:
// Current Hour
hour = cal.get(Calendar.HOUR_OF_DAY);
// Current Minute
minute = cal.get(Calendar.MINUTE);
return new TimePickerDialog(this, timePickerListener, hour, minute, false);
我已完成以下过程到日期选择器对话框。它有效,但对于时间选择器,我找不到任何过程。
日期选择器:
Calendar calendar = Calendar.getInstance();
dialog = new DatePickerDialog(this, onDateSet, cYear, cMonth, cDay);
dialog.getDatePicker().setMinDate(calendar.getTimeInMillis());
所以请帮助如何在时间选择器对话框中实现这一点。
答案 0 :(得分:2)
您可以将此作为起点。
扩展TimePickerDialog并添加了2个方法setMin和setMax。
在onTimeChanged方法中检查新时间相对于最小/最大时间是否有效。
它仍然需要一些抛光......
public class BoundTimePickerDialog extends TimePickerDialog {
private int minHour = -1, minMinute = -1, maxHour = 100, maxMinute = 100;
private int currentHour, currentMinute;
public BoundTimePickerDialog(Context context, OnTimeSetListener callBack, int hourOfDay, int minute, boolean is24HourView) {
super(context, callBack, hourOfDay, minute, is24HourView);
}
public void setMin(int hour, int minute) {
minHour = hour;
minMinute = minute;
}
public void setMax(int hour, int minute) {
maxHour = hour;
maxMinute = minute;
}
@Override
public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {
super.onTimeChanged(view, hourOfDay, minute);
boolean validTime;
if(hourOfDay < minHour) {
validTime = false;
}
else if(hourOfDay == minHour) {
validTime = minute >= minMinute;
}
else if(hourOfDay == maxHour) {
validTime = minute <= maxMinute;
}
else {
validTime = true;
}
if(validTime) {
currentHour = hourOfDay;
currentMinute = minute;
}
else {
updateTime(currentHour, currentMinute);
}
}
}