Question

我正在尝试从PHP文件返回XML结构格式......我应该得到一个预期的结果，如：

<points srv="2381" id="1233"><point id="1233" value1="46" value2="11" value3="231" value4="5516" time_evento="2013-11-13 16:54:17" /><point id="1233"...

但是我得到了这个结果的错误：

.../parsererror.xml">XML parse error: illegal...: https://.../file.php <sourcetext>&lt;points srv="2381" id="1233"&gt;&lt;point id="1233" value1="46" value2="11" value3="231" value4="5516" time_evento="2013-11-13 16:54:17" /&gt;&lt;point id="1233"...

即使在文件中我写了结果，它也能正确保存...

以下是代码：

while ($riga = $db->fetch_object($res))
{
        $rows_found = true;
        if ($riga->srv <> $prev_srv || $riga->id <> $prev_id) {
                if (!$bof) {
                        $xml_document .= '</points>';   // node header
                }
                $xml_document .= '<points srv="'.$riga->srv.'" id="'.$riga->id.'">';
                $bof = false;  
                $prev_srv = $riga->srv;
                $prev_id = $riga->id;
        }

        $xml_document .= '<point id="'.$riga->id.'" value1="'.$riga->val1.'" value2="'.$riga->val2.'" value3="'.$riga->val3.'" ';
        $xml_document .= ' value4="'.$riga->val4.'" ';
        $xml_document .= ' time_evento="'.$riga->time_evento.'"  />';
}
if ($rows_found) {
        $xml_document .= "</points>";
}

$myFile = "/var/tmp/resultXML";
$fh = fopen($myFile, 'w+') or die("can't open file");
fwrite($fh, $xml_document . "\n"); // <---- in the xml_document file I get the correct result
fclose($fh);   

// $xml = new SimpleXMLElement($xml_document);
// echo $xml->asXML();

echo $xml_document;

$db->free_results($res);

if(session_id() == '') {
        session_write_close();
}              
return 0;

有什么建议吗？这让我有点疯狂，三天后我就被困住了......

Answer 1

想出来：看起来XML文档必须有一个根节点，否则就不会形成良好的形状......如：

<root>
   <points ...>
      <point.... />
      <point.... />
      .
      .
      <point.... />
   </points>
   <points...>
      <point.... />
      <point.... />
      .
      .
      <point.... />
   </points>
</root>

非常感谢！

干杯，路易

XML格式化结果返回错误

1 个答案: