Question

目标是让背景不断循环（侧面滚动式游戏）。我在网上发现了一些代码，它在Flash的“动作”面板中工作，但我被告知我的“动作”面板中没有任何内容，并且我的所有代码都必须在ActionScript文件（.as）中。有没有办法在actionscript文件中而不是在操作窗口中执行此代码？怎么样？ - 非常感谢，我真的很感激！

//The speed of the scroll movement.
var scrollSpeed:uint = 2;

//This adds two instances of the movie clip onto the stage.
var s1:ScrollBg = new ScrollBg();
var s2:ScrollBg = new ScrollBg();
addChild(s1); 
addChild(s2);

//This positions the second movieclip next to the first one.
s1.x = 0;
s2.x = s1.width;

//Adds an event listener to the stage.
stage.addEventListener(Event.ENTER_FRAME, moveScroll); 

//This function moves both the images to left. If the first and second 
//images goes pass the left stage boundary then it gets moved to 
//the other side of the stage. 
function moveScroll(e:Event):void{
s1.x -= scrollSpeed;  
s2.x -= scrollSpeed;  

if(s1.x < -s1.width){
s1.x = s1.width;
}else if(s2.x < -s2.width){
s2.x = s2.width;
}
}

Answer 1

package {
  import flash.display.MovieClip;
  import flash.events.Event;

  public class Main extends MovieClip{

    //The speed of the scroll movement.
    var scrollSpeed:uint = 2;

    //This adds two instances of the movie clip onto the stage.
    var s1:ScrollBg = new ScrollBg();
    var s2:ScrollBg = new ScrollBg();
    addChild(s1); 
    addChild(s2);

    //This positions the second movieclip next to the first one.
    s1.x = 0;
    s2.x = s1.width;

    //Adds an event listener to the stage.
    stage.addEventListener(Event.ENTER_FRAME, moveScroll); 

    //This function moves both the images to left. If the first and second 
    //images goes pass the left stage boundary then it gets moved to 
    //the other side of the stage. 
    function moveScroll(e:Event):void{
      s1.x -= scrollSpeed;  
      s2.x -= scrollSpeed;  

      if(s1.x < -s1.width){
        s1.x = s1.width;
      }else if(s2.x < -s2.width){
        s2.x = s2.width;
      }
    }
  }
}

更改您拥有的内容并将其作为.as文件保存到主.fla所在的同一文件夹中。

修改另外，请确保在主.fla文件中主类设置为Main.as，如果您不知道它在哪里，那么只需查找它。

为什么此代码在ActionScript面板中工作，而不在ActionScript文件中？我怎么解决这个问题？

1 个答案: