在我的项目中,我想在点击一个按钮时显示一个jsp页面,并显示父页面(后面)。
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
<style type="text/css">
<!--
.style1 {
font-family: Arial, Helvetica, sans-serif;
font-weight: bold;
font-size: 12px;
}
-->
</style>
<link href="css/buttons.css" rel="stylesheet" type="text/css"/>
</head>
<body>
<form name="form1" method="post" action="analystServlet">
<table width="100%" border="0" cellspacing="1" cellpadding="1">
<tr>
<td> </td>
<td> </td>
</tr>
<tr>
<td><span class="style1">Choose Source</span></td>
<td><select name="source">
<option>Excel</option>
<option>Database</option>
</select></td>
</tr>
<tr>
<td><input type="hidden" name="id" value="494"/></td>
<td> </td>
</tr>
<tr>
<td colspan="2"><div align="center">
<input type="submit" class="button" onclick="hide()" name="exportHome" value="Submit"/>
</div></td>
</tr>
</table>
</form>
</body>
当我点击提交按钮时,此页面已经消失。 谢谢, Karthika KM
答案 0 :(得分:2)
您只能使用ajax / jquery
来完成 function closeMe()
{
window.opener.location.reload(true); // reload parent page
window.close(); // close this page
}
$("#submitbtn").click(function(e) {
e.preventDefault();
var params = {
// here pass form parameter
};
$.ajax({
type: "POST",
url: "/analystServlet",
data: params,
success: function(data){
$('body').css("background", "rgba(0,0,0,0.5)").fadeOut("slow");
setTimeout(function () {
closeMe();
}, 1000); // 1000 = 1 secs
}
}); // end of $.ajax()