Question

考虑我的表

+----+------+--------+----------+
| ID | Name | Salary | Month    |
+----+------+--------+----------+
|  1 | a    |   5000 | Jan      |
|  2 | b    |   5500 | Jan      |
|  3 | b    |   5300 | Feb      |
|  4 | b    |   5300 | Mar      |
|  5 | b    |   5300 | Apr      |
|  6 | b    |   5300 | May      |
|  7 | b    |   5300 | June     |
|  8 | b    |   5300 | July     |
+----+------+--------+----------+

我需要显示

+----+------+--------+----------+
| ID | Name | Salary |  Month   |
+----+------+--------+----------+
|  1 | a    |   5000 | Jan      |
|  2 | b    |   5500 | Jan      |
|  3 |      |   5300 | Feb      |
|  4 |      |   5300 | Mar      |
|  5 |      |   5300 | Apr      |
|  6 |      |   5300 | May      |
|  7 |      |   5300 | June     |
|  8 |      |   5300 | July     |
+----+------+--------+----------+

可以帮助

Answer 1

我假设结果按name列排序（可能然后是工资？），您可以使用分析函数ROW_NUMBER来挑出第一个，并且只打印出来一出。你可能想稍微调整一下查询，但这是主要的想法：

SELECT   id, CASE rn WHEN 1 THEN name ELSE null END, salary, month
FROM     (SELECT id, name, salary, month, 
                 ROW_NUMBER() OVER (PARTITION BY name ORDER BY salary) AS rn
         FROM   some_table)
ORDER BY name, rn

Answer 2

请尝试以下MS Sql server查询：

select  
    a.ID, 
    case when a.Name=b.Name then NULL else a.Name end Name, 
    a.Salary, 
    a.[Month]
from YourTable a left join YourTable b 
  on a.ID=b.ID+1

删除重复的列值

2 个答案: