$.getJSON('<?php echo $this->baseURL()?>/site/ajax/checkusername',
{username: $('#username').val()},
function(data)
{
if (data == "TRUE")
{
$("#available").text("This username is available!");
}
else
{
$("#available").text("This username is not available!");
}
}
);
返回请求网址:
http://my.local/site/ajax/checkusername?username=sdfsdf
我希望以表格形式返回:
http://my.local/site/ajax/checkusername/username/sdfsdf
如何实现这一目标?
答案 0 :(得分:1)
$.getJSON('<?php echo $this->baseURL()?>/site/ajax/checkusername/username/' + encodeURIComponent($('#username').val()),
function(data)
{
if (data == "TRUE")
{
$("#available").text("This username is available!");
}
else
{
$("#available").text("This username is not available!");
}
}
);