好的,这是我在数据库中的表格:
CREATE DATABASE Temp
GO --------------------------
USE Temp
GO --------------------------
CREATE TABLE Table1
(
Table1Id INT IDENTITY(1, 1) ,
Name VARCHAR(20) ,
CONSTRAINT pk_Table1 PRIMARY KEY ( Table1Id )
)
GO --------------------------
CREATE TABLE Table2
(
Table2Id INT IDENTITY(1, 1) ,
Table1Id INT ,
NAME VARCHAR(20) ,
TheDate SMALLDATETIME ,
CONSTRAINT pk_Table2 PRIMARY KEY ( Table2Id ) ,
CONSTRAINT fk_Table2_Table1 FOREIGN KEY ( Table1Id ) REFERENCES Table1 ( Table1Id )
)
GO --------------------------
INSERT INTO Table1
( Name )
VALUES ( 'Stack Overflow' )
GO --------------------------
INSERT INTO Table1
( Name )
VALUES ( 'Expert Sex Change' )
GO --------------------------
INSERT INTO Table1
( Name )
VALUES ( 'Code Project' )
GO --------------------------
INSERT INTO dbo.Table2
( Table1Id ,
NAME ,
TheDate
)
VALUES ( 1 ,
'S1' ,
'11-01-2012'
)
GO --------------------------
INSERT INTO dbo.Table2
( Table1Id ,
NAME ,
TheDate
)
VALUES ( 1 ,
'S2' ,
'11-01-2013'
)
GO --------------------------
INSERT INTO dbo.Table2
( Table1Id ,
NAME ,
TheDate
)
VALUES ( 2 ,
'E1' ,
'10-01-2013'
)
这是我的LINQ:
from t1 in Table1s
join t2 in Table2s.OrderByDescending(x => x.TheDate)
on t1.Table1Id equals t2.Table1Id into tt
from t2 in tt.DefaultIfEmpty()
select new
{
t1.Table1Id,
t1.Name,
t2.NAME,
t2.TheDate
}
这个回归:
Table1Id - Name - NAME - TheDate
1 - 堆栈溢出 - S2 - 11/1/2013
2 - 专家性别变化 - E1 - 10/1/2013
1 - 堆栈溢出 - S1 - 11/1/2012
3 - 代码项目 - null - null
我希望LINQ查询不返回第三行,就像旧日期值一样。
答案 0 :(得分:0)
我想我明白了,答案是:
from t1 in Table1s
join t2 in Table2s
on t1.Table1Id equals t2.Table1Id
into tt
from x in tt.DefaultIfEmpty()
// where ... t1 && x ..
orderby t1.Table1Id
group x by new {t1.Table1Id,t1.Name} into g
select new {
Table1Id = g.Key.Table1Id,
Name = g.Key.Name,
TheDate = g.Max(c => c.TheDate)
}