Question

这是通过实现NSServices来接收NSString并从另一个任何其他应用程序返回NSString的代码正常工作，如下所述：https://developer.apple.com/library/mac/documentation/cocoa/conceptual/SysServices/Articles/properties.html

 - (void)simpleEncrypt:(NSPasteboard *)pboard
             userData:(NSString *)userData error:(NSString **)error {

  // Test for strings on the pasteboard.
  NSArray *classes = [NSArray arrayWithObject:[NSString class]];
  NSDictionary *options = [NSDictionary dictionary];

  if (![pboard canReadObjectForClasses:classes options:options]) {
    *error = NSLocalizedString(@"Error: couldn't encrypt text.",
                               @"pboard couldn't give string.");
    return;
  }
  // Get and encrypt the string.
  NSString *pboardString = [pboard stringForType:NSPasteboardTypeString];
  NSString *newString = [self rotateLettersInString:pboardString];
  if (!newString) {
    *error = NSLocalizedString(@"Error: couldn't encrypt text.",
                               @"self couldn't rotate letters.");
    return;
  }

  // Write the encrypted string onto the pasteboard.
  [pboard clearContents];
  [pboard writeObjects:[NSArray arrayWithObject:newString]];
}

有没有办法获取发件人应用程序所选文本的位置，位置和/或坐标，以便在该位置显示弹出窗口？

Answer 1

当用户通过双击文本选择文本时，您可以捕获并存储鼠标位置。如果您的应用程序在用户从上下文菜单中选择菜单后获得控制权，请使用存储的鼠标位置显示弹出窗口。

- (void)applicationDidFinishLaunching:(NSNotification *)aNotification
{
  [NSEvent addGlobalMonitorForEventsMatchingMask:NSLeftMouseUpMask handler:
    ^(NSEvent *event)
    {
    if([event clickCount] == 2)
    {
        NSPoint mousePointInScreen = [NSEvent mouseLocation];//store this to a member ivar.    
    }
}];

[NSApp setServicesProvider:self];
NSUpdateDynamicServices();
}

- (void) simpleEncrypt:(NSPasteboard *)pboard
          userData:(NSString *)userData
             error:(NSString **)error
 {
    //Get the stored mouse location 
    //Perform other tasks
 }

从发件人应用程序获取NSServices信息时获取文本的位置（坐标）

1 个答案: