如何将列表元素连接在一起并检查元素是否构成某些特定单词之一?并删除每个没有任何单词的元素,并用空格替换它们。我是初学者,所以对我很轻松。
欣赏帮助。
我的代码:
def looking_word_left_to_right(the_list):
for any_words in the_valid_words:
for every in the_list:
for letters_s in every:
index_list=0
有效词:aardvark 信天翁 鳄鱼 犰狳 梭鱼 骆驼 驯鹿 猫 黄牛 麂皮 鸡 鳕鱼 鹿 恐龙 狗 角鲨 dotterel 蜻蜓 鳗鱼 鼬 雀 鱼 火烈鸟 飞 金翅雀 龙 獭 牛 鹿
列表= ['e','l','l','e','z','a','g','c','h','i','c' ,'k','e','n','b','n','d','o'] ['d','e','t','b','a','l','l','i','g','a','t','o',' r','a','a','a','o','l'] ['m','e','z','n','a','c','a','t','t','l','e','e',' b','l','r','c','t','a'] ['c','f','e','n','a','r','c','e','s','s','s','a',' d','l','r','i','t','f'] ['h','f','t','r','a','r','r','s','s','o','s','a',' o','i','a','r','e','f'] ['a','a','r','e','p','p','o','h','s','s','a','r',' g','h','c','e','r','u'] ['m','r','h','e','i','r','m','m','w','i','l','d',' f','c','u','m','e','b'] ['o','我','m','l','t','a','a','i','r','f','o','v','我','n','d','a','l','b'] ['我','g','l','a','l','o','b','e','h','o','e','a',' s','i','a','x','u','e'] ['s','a','b','l','d','i','n','b','b','c','c','r',' h','h','r','t','y','l'] ['r','l','a','h','s','i','f','d','l','o','g','k',' r','c','t','l','a','i'] ['a','r','e','o','g','o','l','d','f','i','n','c',' h','e','f','n','n','d'] ['d','m','n','e','e','p','o','l','e','t','n','a',' r','n','t','a','d','o'] ['d','我','n','o','s','a','u','r','o','x','o','f',' o','e','c','l','i','c'] ['t','n','a','h','p','e','l','e','p','a','l','g',' a','i','e','r','h','o'] ['h','c','a','o','r','k','c','o','c','y','a','t',' r','m','o','a','c','r'] ['f','l','a','m','i','n','g','o','e','r','e','f',' a','f','l','o','e','c'] ['h','a','t','e','e','h','c','h','d','r','a','c',' a','r','i','b','o','u']my_str="ellezagchickenbndodetballigatoraaaolmeznacattleeblrctacfenarcesssadlritfhftrarrssosaoiarefaareppohssarghcerumrheirmmwildfcumeboimltaairfovindalbiglalobehoeasiaxuesabldinbbccrhhrtylrlahsifdlogkrctlaiareogoldfinchefnnddmneepoletnarntadodinosauroxofoeclictnahpelepalgaierhohcaorkcocyatrmoacrflamingoerefafloechateehchdracaribou"
def create_2d_list(N):
output_list=[]
counter=0
for row in range(0,N):
temp=[]
for col in range(0,N):
temp.append(my_str[counter])#you can add a charcter instead of counter
counter=counter+1
output_list.append(temp[:])
return output_list
N=18
x=create_2d_list(N)
for row in range(0,N):
total=0
s="|"
for col in range(0,N):
my_str="{0:2} ".format(x[row][col])
s=s+my_str+"|"
print "-"*(N*4+1)
print s,
print " "
the_valid_words=open("E:/asd/words.txt","r").readlines()
def list_duplicates_of(seq,item):
start_at = -1
locs = []
while True:
try:
loc = seq.index(item,start_at+1)
except ValueError:
break
else:
locs.append(loc)
start_at = loc
return locs
def looking_word_left_to_right(the_list):
for any_words in the_valid_words:
for every in the_list:
for letters_s in every:
index_list=0
答案 0 :(得分:0)
将行转换为字符串可以更轻松地找到目标字词。 the_list需要是一个列表列表才能使用。
row_letters = [''.join(r) for r in the_lists]
words = 'aardvark albatross alligator armadillo barracuda camel caribou cat '
'cattle chamois chicken cod deer dinosaur dog dogfish dotterel '
'dragonfly eel ferret finch fish flamingo fly goldfinch dragon otter '
'ox deer'.split()
for i, row in enumerate(row_letters[:]):
for word in words:
if word in row:
wi = row.find(word)
row_letters[i] = ' '*wi + word + ' '*(len(row) - wi - len(word))
if ' ' not in row_letters[i]: #works if word size < row size
row_letters[i] = ' '*len(row)
>>> row_letters
[' chicken ', ' alligator ', ' cattle ',
' ', ' ', ' ',
' ', ' ', ' ',
' ', ' ', ' goldfinch ',
' ', ' ox ', ' ',
' ', 'flamingo ', ' caribou']
>>> new_the_list = [list(r) for r in row_letters] # puts back to list format