Question

我尝试从CategoryType表单设置字段“author”的值。我希望它是来自使用FOS包登录的当前用户的用户ID。

我的CategoryType表单：

namespace My\CategoryBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;

class CategoryType extends AbstractType
{
    private $userId;

    public function __construct(array $userId)
    {
        $this->userId = $userId;
    }

     /**
     * @param FormBuilderInterface $builder
     * @param array $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('title')
            ->add('author')
            ->add('content')
        ;
    }

    /**
     * @param OptionsResolverInterface $resolver
     */
    public function setDefaultOptions(OptionsResolverInterface $resolver)
    {
        $resolver->setDefaults(array(
            'data_class' => 'My\CategoryBundle\Entity\Category',
            'auteur' => $this->userId
        ));
    }

    /**
     * @return string
     */
    public function getName()
    {
        return 'my_categorybundle_category';
    }
}

我的控制器操作：

public function addAction()
{
    $category = new Category;
    $user = $this->get('security.context')->getToken()->getUser(); 
    $userId = $user->getId();

    $form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));

    $request = $this->get('request');
    if ($request->getMethod() == 'POST') {
        $form->bind($request);

        if ($form->isValid()) {
            $em = $this->getDoctrine()->getManager();
            $em->persist($category);
            $em->flush();

        return $this->redirect($this->generateUrl('mycategory_voir',
            array('id' => $category->getId())));
        }
    }
    return $this->render('MyCategoryBundle:Category:add.html.twig',
        array(
            'form' => $form->createView(),
        ));
}

我在运行操作时遇到此错误：

可捕获的致命错误：传递给My \ CategoryBundle \ Form \ CategoryType :: __ construct（）的参数1必须是数组，没有给定，在第55行的/My/CategoryBundle/Controller/CategoryController.php中调用并在/中定义我的/ CategoryBundle / Form / CategoryType.php第13行

这不是我传递给表单的数组吗？

Answer 1

您的问题就在这一行

$form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));

您不满足My\CategoryBundle\FormCategoryType::__construct()的合同。在这里，让我们以另一种方式看待它。

$form = $this->get('form.factory')->create(
    new CategoryType(/* You told PHP to expect an array here */)
  , array('author' => $userId)
);

作为Symfony\Component\Form\FormFactory::create()的第二个参数发送的数组是最终注入$options数组My\CategoryBundle\Form\CategoryType::buildForm()

的数组

在我看来，你有几种不同的方法可以解决这个问题

更新参数签名并调用My\CategoryBundle\FormCategoryType::__construct()来传递/接收整个用户对象（而不仅仅是他们的id - 请记住，此时您正在使用Doctrine关系，而不是更低级别他们映射到的外键）

namespace My\CategoryBundle\Form;

use My\CategoryBundle\Entity\User; /* Or whatver your User class is */
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;

class CategoryType extends AbstractType
{
    private $author;

    public function __construct( User $author )
    {
        $this->author = $author;
    }

和

$form = $this->get('form.factory')->create(
    new CategoryType(
      $this->get('security.context')->getToken()->getUser()
    )
);

不要将User注入到类型的构造函数中，只是让选项处理它

namespace My\CategoryBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;

class CategoryType extends AbstractType
{
    private $userId;

     /**
     * @param FormBuilderInterface $builder
     * @param array $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('title')
            ->add('author', 'hidden', array('data'=>$options['author']))
            ->add('content')
        ;
    }

    /**
     * @param OptionsResolverInterface $resolver
     */
    public function setDefaultOptions(OptionsResolverInterface $resolver)
    {
        $resolver->setDefaults(array(
            'data_class' => 'My\CategoryBundle\Entity\Category'
        ));
    }

    /**
     * @return string
     */
    public function getName()
    {
        return 'my_categorybundle_category';
    }
}

甚至不打扰将作者放在表单中并让控制器处理它

$form = $this->get('form.factory')->create(
    new CategoryType()
  , array('author' => $this->get('security.context')->getToken()->getUser() )
);

和

if ($request->getMethod() == 'POST') {
    $form->bind($request);

    if ($form->isValid()) {
        $category->setAuthor(
          $this->get('security.context')->getToken()->getUser()
        );
        $em = $this->getDoctrine()->getManager();
        $em->persist($category);
        $em->flush();

    return $this->redirect($this->generateUrl('mycategory_voir',
        array('id' => $category->getId())));
    }
}

将您的表单类型转换为服务，并使用DI容器注入安全上下文

应用/配置/ config.yml

services: form.type.my_categorybundle_category: class: My\CategoryBundle\Form\CategoryType tags: - {name: form.type, alias: my_categorybundle_category} arguments: ["%security.context%"]

更新您的类型以接收安全上下文

namespace My\CategoryBundle\Form; use Symfony\Component\Security\Core\SecurityContext; use Symfony\Component\Form\AbstractType; use Symfony\Component\Form\FormBuilderInterface; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class CategoryType extends AbstractType { private $author; public function __construct( SecurityContext $security ) { $this->author = $security->getToken()->getUser(); }

然后在您的控制器中，创建具有服务名称
的表单
$form = $this->get('form.factory')->create('my_categorybundle_category');

Answer 2

您当前的代码将数组传递给create()方法，而不是CategoryType构造。

$form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));

应该是

$form = $this->get('form.factory')->create(new CategoryType(array( 'author' => $userId)));

Symfony / FOS - 将用户id变量传递给表单Type

2 个答案: