使用json.net在序列化期间合并两个对象?

时间:2013-11-06 11:46:27

标签: c# json serialization json.net

我遇到了以下情况,有人可以帮我实现以下目标吗?

例如,如果我有这个类: -

public class Sample
{
    public String name {get;set;}
    public MyClass myclass {get;set;}
}

我的Myclass将如下:

public class MyClass
{
    public String p1 {get;set;}
    public String p2 {get;set;}
}

当我使用Json.net序列化Sample类的对象时,我得到如下所示,它运行良好。

{
 "name":"...",
 "myclass":
          {
            "p1":"...",
            "p2":"..."
           }
 }

它是正确的,但我想知道是否有可能获得如下的json字符串?

{
 "name":"...",
 "p1":"...",
 "p2":"..."
}

1 个答案:

答案 0 :(得分:22)

您可以创建匿名对象并对其进行序列化:

var sample = new Sample { 
    name = "Bob", 
    myclass = new MyClass { 
                p1 = "x", 
                p2 = "y" 
              }};

string json = JsonConvert.SerializeObject(new { 
                 sample.name, 
                 sample.myclass.p1, 
                 sample.myclass.p2 
              });

结果

{"name":"Bob","p1":"x","p2":"y"}

但我建议您使用Sample类的默认序列化,或者创建将序列化为您的格式的类(即将MyClass属性移动到Sample)。

UPDATE :您可以使用自定义转换器,它会将对象展平并将所有内部对象属性序列化为顶级对象属性:

public class FlattenJsonConverter : JsonConverter
{
    public override void WriteJson(JsonWriter writer, object value, 
        JsonSerializer serializer)
    {
        JToken t = JToken.FromObject(value);
        if (t.Type != JTokenType.Object)
        {
            t.WriteTo(writer);
            return;
        }

        JObject o = (JObject)t;
        writer.WriteStartObject();
        WriteJson(writer, o);
        writer.WriteEndObject();
    }

    private void WriteJson(JsonWriter writer, JObject value)
    {
        foreach (var p in value.Properties())
        {
            if (p.Value is JObject)
                WriteJson(writer, (JObject)p.Value);
            else
                p.WriteTo(writer);
        }
    }

    public override object ReadJson(JsonReader reader, Type objectType, 
       object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }

    public override bool CanConvert(Type objectType)
    {
        return true; // works for any type
    }
}

用法:

string json = JsonConvert.SerializeObject(sample, new FlattenJsonConverter());

或者您可以简单地将匿名类型创建隐藏到自定义转换器中,如果您只需要一种类型的此行为:

public class SampleJsonConverter : JsonConverter
{
    public override void WriteJson(JsonWriter writer, 
        object value, JsonSerializer serializer)
    {
        Sample sample = (Sample)value;
        JToken t = JToken.FromObject(new { 
                      sample.name, 
                      sample.myclass.p1, 
                      sample.myclass.p2 
                   });

        t.WriteTo(writer);
    }

    public override object ReadJson(JsonReader reader, Type objectType,
        object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }

    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Sample);
    }
}