我不久前进入了 Spring Web MVC Framework ,因此我是一个完全的初学者。现在我正在为我的第一个 Web应用程序实现一个基本的表单。
与此同时,我想说我一整天都在为我的问题寻求解决方案。如果类似问题的解决方案已经发布,我会提前解散。
源代码:
弹簧servlet.xml中
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="si.src.controllers" />
<context:component-scan base-package="si.src.validators" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass">
<value>org.springframework.web.servlet.view.JstlView</value>
</property>
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
的index.jsp
<!-- language: lang-jsp -->
<html>
<head>
<title>Spring 3.0 MVC Series - Index</title>
</head>
<body>
<br>
<div align='center'>
<p>
<h1>Example - Spring Application</h1>
The "index.jsp" is the entry point for our application.
This is my first test. Work!
<p>
<a href="login.html">Welcome! Click Here to Login</a>
</div>
</body>
</html>
的login.jsp
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%@ taglib prefix="fmt" uri="http://java.sun.com/jsp/jstl/fmt" %>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form" %>
<html>
<head>
<title>Spring Sample - Login Page</title>
</head>
<body>
<h3>Login Page</h3><br>
<form:form id="form" method="post" commandName="loginForm">
<form:errors path="*" cssClass="errorblock" element="div" />
<table>
<tr>
<td><form:label path="username">Username</form:label></td>
<td><form:input path="username" /></td>
<td><form:errors path="username" cssClass="error"/></td>
</tr>
<tr>
<td><form:label path="username">Password</form:label></td>
<td><form:input path="password" /></td>
<td><form:errors path="password" cssClass="error"/></td>
</tr>
<tr>
<td colspan="2"><input type="submit" value="Sign in" /></td>
</tr>
</table>
</form:form>
</body>
</html>
LoginFormController.java
package si.src.controllers;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.validation.BindException;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.mvc.SimpleFormController;
import org.springframework.web.servlet.ModelAndView;
import si.src.logic.Login;
import si.src.validators.LoginValidator;
@Controller
@RequestMapping(value="/login")
public class LoginFormController extends SimpleFormController{
public LoginFormController(){
setCommandClass(Login.class); //Form's values will store into the Login object
setCommandName("loginForm"); //If HTML form action value with named "loginForm" is sumbitted, Spring will forward request to this form controller
}
@RequestMapping(method=RequestMethod.POST)
protected ModelAndView onSubmit(HttpServletRequest request,
HttpServletResponse response, Object command, BindException errors) throws Exception{
LoginValidator validator = new LoginValidator();
Login userLogin = (Login) command;
validator.validate(userLogin, errors.getBindingResult());
if(errors.hasErrors()){
userLogin.setUsername("");
userLogin.setPassword("");
System.out.println("Ne");
return new ModelAndView("login","loginForm", userLogin);
}
else{
System.out.println(userLogin);
System.out.println(userLogin.getUsername() + " " + userLogin.getPassword());
return new ModelAndView("success","userLogin", userLogin);
}
}
protected Object formBackingObject(HttpServletRequest request) throws Exception {
//Initialize the values in the form. Not necessary
Login userLogin = new Login();
userLogin.setUsername("Admin");
return userLogin;
}
}
LoginValidator.java
package si.src.validators;
import org.springframework.validation.Errors;
import org.springframework.validation.Validator;
import org.springframework.validation.ValidationUtils;
import si.src.logic.Login;
public class LoginValidator implements Validator{
public boolean supports(Class aClass) {
//just validate the Login instances
return Login.class.isAssignableFrom(aClass);
}
public void validate(Object obj, Errors errors) {
Login login = (Login) obj;
ValidationUtils.rejectIfEmptyOrWhitespace(errors, "username","required-username", "Enter username");
ValidationUtils.rejectIfEmptyOrWhitespace(errors, "password","required-password", "Enter password");
}
}
Login.java
package si.src.logic;
public class Login {
private String username;
private String password;
public Login(){}
public void setUsername(String username){
this.username=username;
}
public String getUsername(){
return username;
}
public void setPassword(String password){
this.password=password;
}
public String getPassword(){
return password;
}
}
我认为 LoginValidator 对象获取的错误消息未与我的 login.jsp 文件正确“绑定”。我想这就是错误消息即“输入用户名”和“输入密码”的原因,当我的表单是很难实现。
我的问题是:为什么错误消息没有出现在login.jsp中?
答案 0 :(得分:3)
我有类似的问题。我也改变了返回的类型,但是我需要从控制器到JSP传输日期。我使用对象模型,但是我有与对象modelandview相同的结果。
如何在不丢失表单显示的情况下传输数据:错误?
@RequestMapping(value="/addCaregiver", method= RequestMethod.POST)
public String addCaregiver(@ModelAttribute("caregiver") @Valid
Caregivers caregiver, BindingResult result,Principal principal, Model model){
caregiverValidator.validate(caregiver, result);
if(result.hasErrors()){
model.addAttribute("caregivers",pp.getCaregiverses(principal.getName()));
model.addAttribute("error", "true");
model.addAttribute("caregiver", new Caregivers());
return "caregiver";
}
return "intro";
}
我解决了,不创造新的利益,我删除了这一行:
model.addAttribute("caregiver", new Caregivers());
答案 1 :(得分:2)
return new ModelAndView("login","loginForm", userLogin);
你自己正在摧毁这个模型。您正在使用新模型自己构建ModelAndView
,忽略/放弃当前模型。因此,也会破坏绑定错误。
此外,您的代码有误,您正在扩展SimpleFormController
Controller
,并使用@Controller
对其进行注释。这是等待发生的麻烦,删除不推荐使用的extends SimpleFormController
。
将您的控制器更改为此类
@Controller
@RequestMapping(value="/login")
public class LoginFormController {
@ModelAttribute("loginForm")
public Login loginForm() {
return new Login();
userLogin.setUsername("Admin");
return userLogin;
}
@RequestMapping(method=RequestMethod.POST)
public String submit(@ModelAttribute Login loginForm, BindingResult model) {
LoginValidator validator = new LoginValidator();
validator.validate(loginForm, model);
if(errors.hasErrors()){
loginForm.setUsername("");
loginForm.setPassword("");
System.out.println("Ne");
return "login";
} else{
System.out.println(loginForm);
System.out.println(loginForm.getUsername() + " " + loginForm.getPassword());
return "success";
}
}
}