Question

所以我试图复制适用于一个元素的所有样式（class / id / tagName / attribute等）。到目前为止，我发现我可以复制元素的计算样式，只有一个问题... couldend将它应用于其他元素; /

或diffrend复制所有样式的方式。

   //queriks mode + minor changes to retrive the computed style
function getCS(el)
{
    if (el.currentStyle)
        var y = el.currentStyle;
    else if (window.getComputedStyle)
        var y = document.defaultView.getComputedStyle(el,null);
    return y;
}
function setCS(el,cs)
{
    if (el.currentStyle)
    {

        el.currentStyle = cs;
        el.style = cs;
    }
    else if (window.getComputedStyle)
    {el.style = cs 
    }

}


var myLink = document.getElementById('myLink');
var anotherLink = document.getElementById('anotherLink');

var CS_myLink = getCS(myLink);
setCS(anotherLink,CS_myLink);

Answer 1

更新：正如@ icl7126建议的那样，这里有一个更短的版本，实际上用于相同的用法。好的一点是要记住，如果没有预先编译，这段代码就无法在大多数/旧版浏览器上运行。

Original（ES 2017）：

function copyNodeStyle(sourceNode, targetNode) {
  const computedStyle = window.getComputedStyle(sourceNode);
  Array.from(computedStyle).forEach(key => targetNode.style.setProperty(key, computedStyle.getPropertyValue(key), computedStyle.getPropertyPriority(key)))
}

预编译（ES 5）：

function copyNodeStyle(sourceNode, targetNode) {
  var computedStyle = window.getComputedStyle(sourceNode);
  Array.from(computedStyle).forEach(function (key) {
    return targetNode.style.setProperty(key, computedStyle.getPropertyValue(key), computedStyle.getPropertyPriority(key));
  });
}

多数民众赞成！我明白了：）

我看到很多人都看到这个问题，所以下面是更详细和干净的代码。

var copyComputedStyle = function(from,to){
    var computed_style_object = false;
    //trying to figure out which style object we need to use depense on the browser support
    //so we try until we have one
    computed_style_object = from.currentStyle || document.defaultView.getComputedStyle(from,null);

    //if the browser dose not support both methods we will return null
    if(!computed_style_object) return null;

        var stylePropertyValid = function(name,value){
                    //checking that the value is not a undefined
            return typeof value !== 'undefined' &&
                    //checking that the value is not a object
                    typeof value !== 'object' &&
                    //checking that the value is not a function
                    typeof value !== 'function' &&
                    //checking that we dosent have empty string
                    value.length > 0 &&
                    //checking that the property is not int index ( happens on some browser
                    value != parseInt(value)

        };

    //we iterating the computed style object and compy the style props and the values 
    for(property in computed_style_object)
    {
        //checking if the property and value we get are valid sinse browser have different implementations
            if(stylePropertyValid(property,computed_style_object[property]))
            {
                //applying the style property to the target element
                    to.style[property] = computed_style_object[property];

            }   
    }   

};

Answer 2

使用setProperty，getPropertyValue和getPropertyPriority的简短解决方案。

function copyNodeStyle(sourceNode, targetNode) {
  const computedStyle = window.getComputedStyle(sourceNode);
  Array.from(computedStyle).forEach(key => targetNode.style.setProperty(key, computedStyle.getPropertyValue(key), computedStyle.getPropertyPriority(key)))
}

有用的MDN文档：getComputedStyle和CSSStyleDeclaration

Answer 3

计算的样式不会保留优先级信息（jsonChain），因此... !important将不会返回样式优先级，因此上面的getComputedStyle()（在可接受的答案中）将不起作用-它将始终返回computedStyle.getPropertyPriority(key)。

如果要确保计算的样式始终具有优先级，则显式设置优先级：

''

将javascript计算样式从一个元素设置/复制到另一个元素

3 个答案: