Question

此任务是根据游戏角色确定两个属性，力量和技能之间的差异。这个过程是：

确定强度属性之间的差异。
将差异除以5并向下舍入以创建“强度修改器”。
对技能属性执行相同的过程并命名为“技能修饰符”。
然后比赛开始：
- 两位玩家都会抛出六面骰子。
- 如果值相同，则不会发生任何变化。
- 如果值不同，那么具有最高值的玩家将获得之前计算出的力量和技能，然后将其添加到总数中。具有最低价值的玩家具有从他们的总数中获得的力量和技能。

这必须重复，直到strength属性等于或低于0，但是，这部分我不能这样做，我知道如何循环，但这总是通过询问用户是否希望再次进行来完成。

c1sc=random.randint(1,6)
c2sc=random.randint(1,6)
if c1sc > c2sc:
    c1st=c1st+strengthmodifier
    c2st=c2st-strengthmodifier
    c1sk=c1sk+skillmodifier
    c2sk=c2sk-skillmodifier
    print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
    print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
elif c2sc > c1sc:
    c1st=c1st-strengthmodifier
    c2st=c2st+strengthmodifier
    c1sk=c1sk-skillmodifier
    c2sk=c2sk+skillmodifier
    print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
    print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
else:
    print('It\'s a draw, no changes were made.')
if c1sk < 0:
    c1sk=0
elif c2sk < 0:
    c2sk=0

if c1st < 0:
    print('Character 1 died. Game over.')
elif c2st < 0:
    print('Character 2 died. Game over.')

请帮忙！

Answer 1

让我向您介绍while循环。如果指定的条件为true或false，则在希望发生某些事情时使用此方法。

我简要编辑了你的代码。

导入随机

def main():
 player1=20
 player2=12
 strength=(20-10)/5
 strength_mod=int(strength)
 while player1>0 and player2>0:
  dice1=random.randint(1,6)
  dice2=random.randint(1,6)
  if dice1>dice2:
    player1+=strength_mod
    player2-=strength_mod
    print("Player 1 strength is:  ", player1)
    print("Player 2 strength is:  ", player2)
  elif dice1<dice2:
    player2+=strength_mod
    player1-=strength_mod
    print("Player 1 strength is:  ", player1)
    print("Player 2 strength is:  ", player2)

main()

我给了玩家1和2个初始值，可以根据自己的喜好进行更改。为了向下舍入，我创建了另一个变量并将强度更改为整数。

Answer 2

添加另一个循环来进行缩减...

c1sc=random.randint(1,6)
c2sc=random.randint(1,6)
if c1sc > c2sc:
    while c2st > 0 and c2sk > 0:
        c1st=c1st+strengthmodifier
        c2st=c2st-strengthmodifier
        c1sk=c1sk+skillmodifier
        c2sk=c2sk-skillmodifier
        print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
        print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
elif c2sc > c1sc:
    while c1st > 0 and c1sk > 0:
        c1st=c1st-strengthmodifier
        c2st=c2st+strengthmodifier
        c1sk=c1sk-skillmodifier
        c2sk=c2sk+skillmodifier
        print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
        print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
else:
    print('It\'s a draw, no changes were made.')
if c1sk < 0:
    c1sk=0
elif c2sk < 0:
    c2sk=0

if c1st < 0:
    print('Character 1 died. Game over.')
elif c2st < 0:
    print('Character 2 died. Game over.')

当然，有更简洁的方式来写这个。这仍然不理想，但代码减少......

c1sc=random.randint(1,6)
c2sc=random.randint(1,6)
if c1sc != c2sc:
    while c1st > 0 and and c2st > 0:
        c1st += strengthmodifier if c1sc > c2sc else -1 * strengthmodifier
        c2st += strengthmodifier if c1sc < c2sc else -1 * strengthmodifier
        c1sk += skillmodifier if c1sc > c2sc else -1 * skillmodifier
        c2sk += skillmodifier if c1sc < c2sc else -1 * skillmodifier
        print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
        print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
    c1sk = math.max(c1sk, 0) # Clamp skill to a minimum of 0
    c2sk = math.max(c2sk, 0) # ...

    if c1st < c2st:
        print('Character 1 died. Game over.')
    else:
        print('Character 2 died. Game over.')
else:
    print('It\'s a draw, no changes were made.')

最后，假设每轮都重新滚动......

while c1st > 0 and and c2st > 0:
    c1sc=random.randint(1,6)
    c2sc=random.randint(1,6)
    if c1sc != c2sc:
        c1st += strengthmodifier if c1sc > c2sc else -1 * strengthmodifier
        c2st += strengthmodifier if c1sc < c2sc else -1 * strengthmodifier
        c1sk += skillmodifier if c1sc > c2sc else -1 * skillmodifier
        c2sk += skillmodifier if c1sc < c2sc else -1 * skillmodifier
        print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
        print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
    else:
        print('It\'s a draw, no changes were made.')


    c1sk = math.max(c1sk, 0) # Clamp skill to a minimum of 0
    c2sk = math.max(c2sk, 0) # ...

if c1st < c2st:
    print('Character 1 died. Game over.')
else:
    print('Character 2 died. Game over.')

Answer 3

这样你就可以得到图片:(伪代码）

while (c2sk > 0 && c1sk > 0)
    //do complete everything up until the if statements
if c1st <0
    print "c1st died" 
elif c2st <0
    print "c2st died"

不确定这是否正是您正在寻找的。如果c2sk和c1sk应该在每次进入循环时被随机重新分配。

如何循环代码直到创建某个数字？

3 个答案: