Question

我有一个arraylist，其中包含以下格式的标题和全名

Dr.|ricardo bettati
Prof. Dr.-Ing.|Helmut sperling
miss|angela link

首先我将内容与|分开。我将获得标题和全名。然后我用空格分割全名，以获得firstname和familyname.

现在我有3个字符串

字符串标题\，其中包含上面列表中的标题字符串名字; String familynames;

接下来的任务是我使用上面的字符串firstname和familyname检查现有xml的文本内容。这是现有的xml

<person>
 <name>
   <firstname>Jean-Luc</firstname>
   <familyname>DeLorme</familyname>
 </name>
</person>
<person>
 <name>
   <firstname>Dave</firstname>
   <familyname>Sperling</familyname>
 </name>
</person>
<person>
 <name>
    <firstname>Helmut</firstname>
    <familyname>sperling</familyname>
 </name>
</person>

如果firstname和familyname条款与上述xml元素<firstname>，<familyname>的文本内容匹配，那么我必须创建一个名为<title>的元素并从我的列表中附加相应的标题。我的XML应该如下所示

<person>
 <name>
   <firstname>Jean-Luc</firstname>
   <familyname>DeLorme</familyname>
 </name>
</person>
<person>
 <name>
   <firstname>Dave</firstname>
   <familyname>Sperling</familyname>
 </name>
</person>
<person>
 <name>
    **<title>Prof. Dr.-Ing.>/title>**
    <firstname>Helmut</firstname>
    <familyname>sperling</familyname>
 </name>
</person>

我尝试使用以下代码

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        dbf.setValidating(false);
        DocumentBuilder db = dbf.newDocumentBuilder();
        Document doc = db.parse(new FileInputStream(new File("Final-Results.xml")));
        Element element =  doc.getDocumentElement();
        NodeList list = doc.getElementsByTagName("person");
        for (int i=0;i<titles.size();i++) { //Title is my arraylist
            String names = (String) titles.get(i);
            String[] content=names.split("\\|");
            String title=content[0];
            String[] fullname=content[1].split("\\s+");
            String firstname=fullname[0];
            String familyname=fullname[1];
            for (int n = 0; n < list.getLength(); n++) {

                   Node node = list.item(n);
                   if ("firstname".equals(node.getNodeName()) && node.getTextContent().equals(firstname)) {
                    System.out.println("haii");
                   }
            }
        }

但是我如何让孩子们检查文本内容并在特定的地方创建节点？

Answer 1

Child node appending:
    Element childElement = doc.createElement("title");
    // set attributes, etc
    node.appendChild(childElement);

可以使用xPath简化代码，例如：

    String xPathExpression = "*/person/name[firstname/text() = 'Helmut' and familyname/text() = 'sperling']";
    XPath path = XPathFactory.newInstance().newXPath();
    NodeList nl = (NodeList) path.evaluate(xPathExpression, doc, XPathConstants.NODESET);
    for (int i = 0; i < nl.getLength(); i++) {
        Element childElement = doc.createElement("title");
        childElement.appendChild(doc.createTextNode("Dr."));
        nl.item(i).insertBefore(childElement,((Element)nl.item(i)).getFirstChild());
    }

如果在指定示例上运行代码，则结果为：

<?xml version="1.0" encoding="UTF-8" standalone="no"?><result>
<person>
 <name>
   <firstname>Jean-Luc</firstname>
   <familyname>DeLorme</familyname>
 </name>
</person>
<person>
 <name>
   <firstname>Dave</firstname>
   <familyname>Sperling</familyname>
 </name>
</person>
<person>
 <name><title>Dr.</title>
    <firstname>Helmut</firstname>
    <familyname>sperling</familyname>
 </name>
</person>
</result>

比较xml元素的文本内容，并将子元素添加到Java中的特定节点

1 个答案: