Greetings Stack Overflow用户,今晚我来找你,帮助我创建一个Java程序。我对Java比较新,所以请原谅我对这个主题的无知。我制作了一个Java程序,它是一个“Rock”“Paper”“Scissors”游戏,其中一个语句中似乎有错误。
import java.util.Scanner;
public class TheAntlers {
public static void main(String[] args) {
int playerHumanWins = 0;
int playerComputerWins = 0;
int numberOfTies = 0;
int computerResult;
Scanner input = new Scanner(System.in);
while(true) {
String startGame;
String playerHuman;
String playerComputer = " ";
System.out.print("Do you want to play \"Rock\", \"Paper\", \"Scissors\"? (Y/N): ");
startGame = input.nextLine();
startGame = startGame.toUpperCase();
if(startGame.equals("N")) {
System.out.println("NO!");
break;
}
else if(! startGame.equals("Y")) {
startGame = startGame.toLowerCase();
System.out.println("Sorry, " + startGame + " is not a valid entry...");
}
while(startGame.equals("Y")) {
System.out.print("Please choose \"Rock\", \"Paper\", or \"Scissors\": ");
playerHuman = input.nextLine();
computerResult = (int)(Math.random() * 3);
playerHuman = playerHuman.toUpperCase();
if(computerResult == 1) {
playerComputer = "ROCK";
}
else if(computerResult == 2) {
playerComputer = "PAPER";
}
else if (computerResult == 3) {
playerComputer = "SCISSORS";
}
switch (playerHuman) {
case "ROCK" :
if(playerComputer.equals(playerHuman)) {
System.out.println("Tie you both picked \"ROCK\"");
numberOfTies++;
}
else if(playerComputer.equals("PAPER")) {
System.out.println("Computer wins!");
playerComputerWins++;
}
else {
System.out.println("You win, \"ROCK\" beats " + "\"" + playerComputer + "\"");
playerHumanWins++;
return;
}
break;
case "PAPER" :
if(playerComputer.equals(playerHuman)) {
System.out.println("Tie you both picked \"PAPER\"");
numberOfTies++;
}
else if(playerComputer.equals("ROCK")) {
System.out.println("You win, \"PAPER\" beats " + "\"" + playerComputer + "\"");
playerHumanWins++;
return;
}
else {
System.out.println("Sorry, the computer won!");
playerComputerWins++;
}
break;
case "SCISSORS" :
if(playerComputer.equals(playerHuman)) {
System.out.println("Tie you both picked \"SCISSORS\"");
numberOfTies++;
}
else if(playerComputer.equals("PAPER")) {
System.out.println("You win, \"SCISSORS\" beats " + "\"" + playerComputer + "\"");
playerHumanWins++;
return;
}
else {
System.out.println("Sorry, the computer won!");
playerComputerWins++;
}
break;
default:
playerHuman = playerHuman.toLowerCase();
System.out.println("Sorry, " + playerHuman + " is not a valid entry...");
break;
}
}
}
}
}
我面临的问题与中奖计算有关。当我运行程序并且我反复进入摇滚直到我获胜时,输出将是你赢了,“ROCK”击败“但是除了任何其他选项我得到你赢了,”ROCK“击败“PAPER”
我的问题是,为什么我在玩摇滚时会得到一个空的回调?
* 此外,如果您愿意指出任何其他建议,以帮助一个很棒的新手。 *
答案 0 :(得分:5)
Math.random() * 3
是一个至少为0且小于3的数字。
将其转换为int后,它为0,1或2。
if(computerResult == 0) {
playerComputer = "ROCK";
}
else if(computerResult == 1) {
playerComputer = "PAPER";
}
else if (computerResult == 2) {
playerComputer = "SCISSORS";
}
建议:
简明扼要。你可以改变
String startGame;
startGame = input.nextLine();
startGame = startGame.toUpperCase();
到
String startGame = input.nextLine().toUpperCase();
当您不必滚动和滚动时,它更具可读性。
另外,请知道equalsIgnoreCase()
存在。
答案 1 :(得分:1)
这不是一个完整的新手,但我会使用以下代码为游戏建模:
enum Choice { ROCK, PAPER, SCISSORS }
enum Result { COMPUTER_WINS, TIE, HUMAN_WINS }
Result decide(Choice computer, Choice human) {
if (human == computer) {
return Result.TIE;
} else if (…) {
…
}
}
通过这种方式,您可以使用部分代码来处理游戏本身,而其他一些代码则处理用户交互。
答案 2 :(得分:0)
你会发现(int)(Math.random()* 3)有时会导致0而从不会导致3,这就是给你空白的结果,因为你没有0的结果。
具体来说,当Math.random()返回小于.33
时