Question

我有一个users表，其中包含product列。

我想知道我桌上有多少产品

Users表

+----------+
| Products |
+----------+
| A        |
| B        |
| A,c      |
| C,B,A    |
| D        |
+----------+

即。 A的计数为：3，B的计数为：2，C的计数为：2，D的计数为：1

Answer 1

请尝试：

SELECT Products, COUNT(Products)
FROM(
    SELECT 
         Split.a.value('.', 'VARCHAR(100)') AS Products
    FROM  
    (
         SELECT
          CAST ('<M>' + REPLACE(Products, ',', '</M><M>') + '</M>' AS XML) AS CVS  
        from YourTable
    ) AS A CROSS APPLY CVS.nodes ('/M') AS Split(a)
)x GROUP BY Products

Answer 2

使用递归查询 - 在2列上进行递归拆分的步骤 - l - 包含不带逗号的条目和r - Products的尾部，之后生成GROUP BY by l列：

WITH expandProd as(
    SELECT
        CASE 
            WHEN charindex(',', Products) < 1 THEN Products
            ELSE LEFT(Products, charindex(',', Products)-1)
        END as l, -- the column without comma
        CASE 
            WHEN charindex(',', Products) < 1 THEN NULL
            ELSE RIGHT(Products, LEN(Products) - charindex(',', Products))
        END as r -- the column with tail
     FROM prods 
     UNION ALL --recursive query that enters again to itself
     SELECT 
         CASE 
             WHEN charindex(',', r) < 1 THEN r
             ELSE LEFT(r, charindex(',', r)-1)
         END as l, 
         CASE 
             WHEN charindex(',', r) < 1 THEN NULL
             ELSE RIGHT(r, LEN(r) - charindex(',', r))
         END as r 
     FROM expandProd 
 WHERE r is not null --small optimization
)
SELECT l, COUNT(l) 
    FROM expandProd
    GROUP BY l

SQL Server 2008中以逗号分隔的字段中的组计数值

2 个答案: