问题是我不知道如何在使用均值滤波器时正确完成数学运算。所有9个内核中的3x3内核,权重值为1。我得到了一些使用总和部分的帮助,但我不知道它是否正常工作,我当然无法建立。
#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <iostream>
using namespace cv;
using namespace std;
int main()
{
Mat gray_image, convolued_image;
gray_image = imread( "C:/1.jpg", CV_LOAD_IMAGE_GRAYSCALE); // Read the file
convolued_image = gray_image;
if(!gray_image.data ) // Check for invalid input
{
cout << "Could not open or find the image" << std::endl ;
return -1;
}
namedWindow( "RGB Input", CV_WINDOW_AUTOSIZE );
imshow( "RGB Input", gray_image );
Mat meanImg;
gray_image.copyTo(meanImg);
namedWindow( "meanImg", CV_WINDOW_AUTOSIZE );
imshow( "meanImg", meanImg );
waitKey(0);
for (int y = 0; y < gray_image.rows; y++)
{
for (int x = 0; x < gray_image.cols; y++)
{
int intesity = gray_image.at<uchar>(y,x);
int sum = gray_image.at<uchar>(y+1,x+1);
sum = gray_image.at<uchar>(y+1,x);
sum = gray_image.at<uchar>(y+1,x-1);
sum = gray_image.at<uchar>(y,x-1);
sum = gray_image.at<uchar>(y,x+1);
sum = gray_image.at<uchar>(y-1,x-1);
sum = gray_image.at<uchar>(y+1,x);
sum = gray_image.at<uchar>(y+1,x+1);
int mean = sum/9;
meanImg.at<uchar>(y,x) = mean;
}
}
return 0;
}
答案 0 :(得分:3)
sum = gray_image.at<uchar>(y+1,x);
sum = gray_image.at<uchar>(y+1,x-1);
sum = gray_image.at<uchar>(y,x-1);
您的变量名为sum
,但您实际上并未在此处添加任何内容。
你也可以通过在图像边界外读取来开始你的循环。
答案 1 :(得分:0)
一旦你建立起来,你就会有这些错误:
你在
中遗漏了一个角色sum = gray_image.at<uchar>(y+1,x);
这些行用新值替换sum
的值。
要将它们实际添加到一起,请执行
sum += gray_image.at<uchar>(y+1,x);
您还要在图像范围之外编制索引 - 您需要正确处理x
或y
为0或其各自最大值的情况。
在内部循环中,您说y++
,您应该说x++
。