我目前正在处理用于将字符串解析为链表的代码,并使用该列表作为计算操作的方法。如图所示,我将操作字符串设置为“1 + 2”,运行时返回整数0.
非常感谢所有帮助。
import java.awt.Dimension;
import java.util.LinkedList;
import java.util.List;
public class LinkedListCalculator {
static List<String> CalcInput = new LinkedList<String>();
static String operation = "1+2";
static int equationLength = operation.length();
static int result = 0;
static int num = 0;
static int mul = 1;
static int finalNum = 0;
static char lastOperator = 0;
public static void addToList() {
String finalNumString;
if (lastOperator == '+') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("+");
} else if (lastOperator == '-') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("-");
} else if (lastOperator == '*') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("*");
} else if (lastOperator == '/') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("/");
}
}
public static void computeList() {
int size = CalcInput.size();
String lastIndex = null;
for (int i = 0; i > size; i++) {
String currentIndex = CalcInput.get(i);
if (i > 0) {
lastIndex = CalcInput.get(i - 1);
}
if (currentIndex == "+") {
int lastIndexInt = Integer.valueOf(lastIndex);
result += lastIndexInt;
}
if (currentIndex == "-") {
int lastIndexInt = Integer.valueOf(lastIndex);
result -= lastIndexInt;
}
if (currentIndex == "*") {
int lastIndexInt = Integer.valueOf(lastIndex);
result *= lastIndexInt;
}
if (currentIndex == "/") {
int lastIndexInt = Integer.valueOf(lastIndex);
result /= lastIndexInt;
}
}
}
public static void main(String [] args) {
for (int currEqnCharNdx = 0; currEqnCharNdx < equationLength ; currEqnCharNdx++) {
char j = operation.charAt(currEqnCharNdx);
if (j >= '0' && j <= '9') {
num = j - '0';
finalNum *= mul;
finalNum += num;
mul = 10;
} else if (operation.charAt(currEqnCharNdx) == '+') {
addToList();
lastOperator = '+';
mul = 1;
finalNum = 0;
} else if (operation.charAt(currEqnCharNdx) == '-') {
addToList();
lastOperator = '-';
mul = 1;
finalNum = 0;
} else if (operation.charAt(currEqnCharNdx) == '*') {
addToList();
lastOperator = '*';
mul = 1;
finalNum = 0;
} else if (operation.charAt(currEqnCharNdx) == '/') {
addToList();
lastOperator = '/';
mul = 1;
finalNum = 0;
}
}
int i = CalcInput.size();
computeList();
System.out.println("result: " + result);
}
}
答案 0 :(得分:0)
您的代码有很多错误。以下是一些错误指示:
String lastIndex = null;
for (int i = 0; i > size; i++) {
这将永远不会执行(更改为i&lt; size)
我还怀疑addToList()应该在设置lastOperator之后发生等等。
else if (operation.charAt(currEqnCharNdx) == '+') {
addToList();
lastOperator = '+';
mul = 1;
finalNum = 0;
}
此外,这里(在addToList()中):
if (lastOperator == '+') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("+");
}
你添加了最后一个数字加上+号,但是之后没有任何东西会导致2被添加,所以当它在最后总结时(如果你修复了我提到的其他东西)它将总和1+结果为1(而不是1 + 2使得3)。
以下是输出1的代码(参见上面的最后一点),以便OP重现:
import java.awt.Dimension;
import java.util.LinkedList;
import java.util.List;
import java.util.StringTokenizer;
public class LinkedListCalculator {
static List<String> CalcInput = new LinkedList<String>();
static String operation = "1+2";
static int equationLength = operation.length();
static int result = 0;
static int num = 0;
static int mul = 1;
static int finalNum = 0;
static char lastOperator = 0;
public static void addToList() {
String finalNumString;
if (lastOperator == '+') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("+");
} else if (lastOperator == '-') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("-");
} else if (lastOperator == '*') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("*");
} else if (lastOperator == '/') {
finalNumString = Integer.toString(finalNum);
CalcInput.add(finalNumString);
CalcInput.add("/");
}
}
public static void computeList() {
int size = CalcInput.size();
String lastIndex = null;
for (int i = 0; i < size; i++) {
String currentIndex = CalcInput.get(i);
if (i > 0) {
lastIndex = CalcInput.get(i - 1);
}
if (currentIndex == "+") {
int lastIndexInt = Integer.valueOf(lastIndex);
result += lastIndexInt;
}
if (currentIndex == "-") {
int lastIndexInt = Integer.valueOf(lastIndex);
result -= lastIndexInt;
}
if (currentIndex == "*") {
int lastIndexInt = Integer.valueOf(lastIndex);
result *= lastIndexInt;
}
if (currentIndex == "/") {
int lastIndexInt = Integer.valueOf(lastIndex);
result /= lastIndexInt;
}
}
}
public static void main(String [] args) {
for (int currEqnCharNdx = 0; currEqnCharNdx < equationLength ; currEqnCharNdx++) {
char j = operation.charAt(currEqnCharNdx);
if (j >= '0' && j <= '9') {
num = j - '0';
finalNum *= mul;
finalNum += num;
mul = 10;
} else if (operation.charAt(currEqnCharNdx) == '+') {
lastOperator = '+';
addToList();
mul = 1;
finalNum = 0;
} else if (operation.charAt(currEqnCharNdx) == '-') {
addToList();
lastOperator = '-';
mul = 1;
finalNum = 0;
} else if (operation.charAt(currEqnCharNdx) == '*') {
addToList();
lastOperator = '*';
mul = 1;
finalNum = 0;
} else if (operation.charAt(currEqnCharNdx) == '/') {
addToList();
lastOperator = '/';
mul = 1;
finalNum = 0;
}
}
int i = CalcInput.size();
computeList();
System.out.println("result: " + result);
}
}