Warning: spl_object_hash() expects parameter 1 to be object, string given in
/var/www/sitetwo/vendor/doctrine/orm/lib/Doctrine/ORM/UnitOfWork.php line 1367
我通过php app / console命令使用yml映射注释创建了带有Category.php
和Product.php
的MainBlogBundle。在使用CRUD操作添加/编辑/删除/显示操作后,我尝试添加一个类别,在提交Add category form
之后我得到了
Warning: spl_object_hash() expects parameter 1 to be object, string given in
/var/www/sitetwo/vendor/doctrine/orm/lib/Doctrine/ORM/UnitOfWork.php line 1367
我在github上发布了我的示例代码,下面是数据库的脚本。
git@github.com:veerpartap/ProblemSymfony.git
/****************************************************************************/
-- phpMyAdmin SQL Dump
-- version 3.4.10.1deb1
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Oct 26, 2013 at 01:56 PM
-- Server version: 5.5.32
-- PHP Version: 5.5.3-1+debphp.org~precise+2
SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";
--
-- Database: `sitetwo`
--
-- --------------------------------------------------------
--
-- Table structure for table `category`
--
CREATE TABLE IF NOT EXISTS `category` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ;
-- --------------------------------------------------------
--
-- Table structure for table `Company`
--
CREATE TABLE IF NOT EXISTS `Company` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`company_name` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`address` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`owner_name` varchar(150) COLLATE utf8_unicode_ci NOT NULL,
`status` tinyint(1) NOT NULL,
`created` datetime NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=3 ;
--
-- Dumping data for table `Company`
--
INSERT INTO `Company` (`id`, `company_name`, `address`, `owner_name`, `status`, `created`) VALUES
(1, 'My First Company', 'Street 5A Sector 85 Chandigarh 1665588', 'Mr. Prateek Kumar', 1, '2013-09-06 00:00:00'),
(2, 'My Second Private Company', 'Street 34N Sector 89, Chandigarh 165898', 'Mr. Saurabh Shuja', 1, '2013-09-07 00:00:00');
-- --------------------------------------------------------
--
-- Table structure for table `Post`
--
CREATE TABLE IF NOT EXISTS `Post` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(250) COLLATE utf8_unicode_ci NOT NULL,
`body` longtext COLLATE utf8_unicode_ci NOT NULL,
`published` datetime NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ;
-- --------------------------------------------------------
--
-- Table structure for table `posts`
--
CREATE TABLE IF NOT EXISTS `posts` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(250) COLLATE utf8_unicode_ci NOT NULL,
`body` longtext COLLATE utf8_unicode_ci NOT NULL,
`published` datetime NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ;
-- --------------------------------------------------------
--
-- Table structure for table `products`
--
CREATE TABLE IF NOT EXISTS `products` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`category_id` int(11) DEFAULT NULL,
`name` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`price` decimal(10,0) NOT NULL,
`description` longtext COLLATE utf8_unicode_ci NOT NULL,
PRIMARY KEY (`id`),
KEY `IDX_B3BA5A5A12469DE2` (`category_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ;
-- --------------------------------------------------------
--
-- Table structure for table `User`
--
CREATE TABLE IF NOT EXISTS `User` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`first_name` varchar(150) NOT NULL,
`last_name` varchar(150) NOT NULL,
`sex` tinyint(1) DEFAULT NULL,
`date_of_birth` datetime DEFAULT NULL,
`education` varchar(10) NOT NULL,
`mobile` varchar(10) NOT NULL,
`email` varchar(100) NOT NULL,
`address` varchar(200) NOT NULL,
`status` tinyint(1) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;
--
-- Dumping data for table `User`
--
INSERT INTO `User` (`id`, `first_name`, `last_name`, `sex`, `date_of_birth`, `education`, `mobile`, `email`, `address`, `status`) VALUES
(1, 'Veerpartap', 'Singh', 1, '2008-11-24 00:00:00', 'MCA', '71505897', 'metveerpartapsingh@gmail.com', 'hl 99 phase 2 sas nagar mohali', 1),
(2, 'Vicky', 'Sharma', 1, '2008-05-09 00:00:00', 'MCA', '88754257', 'vicky.sharma@gmail.com', 'Village Burari, Jila Nawanshar', 1);
--
-- Constraints for dumped tables
--
--
-- Constraints for table `products`
--
ALTER TABLE `products`
ADD CONSTRAINT `FK_B3BA5A5A12469DE2` FOREIGN KEY (`category_id`) REFERENCES `category` (`id`);
/****************************************************************************/
答案 0 :(得分:0)
如上述评论中所述,问题在于我没有在控制器文件中包含Arrarycollection命名空间。但是在包含命名空间后,我在添加新产品时遇到了另一个错误。
以下是错误消息: “__toString()”方法对于选择字段的Main \ BlogBundle \ Enity \ Category类型的对象没有foudn。
对于此错误,我们需要向Category实体添加__toString()方法。例如:
public function __toString() { return $this->name; }
PHP魔术方法__toString()用于呈现对象的文本表示。在这种情况下,在相关实体的表单中选择类别时将使用类别名称。
答案 1 :(得分:0)
如果在类XxxxxType中得到__toString()错误,则扩展AbstractType 你可以在构建器中添加fiel定义,就像这样。无需修改您的实体。
$builder
->add('enquete','entity',array('class' => 'AdequatSipBundle:Enquete',
'property' => 'Id', 'read_only'=>true))
->add('produit','entity',array('class' => 'AdequatSipBundle:Produit',
'property' => 'Name', 'read_only'=>true))