以下是我正在努力工作的代码:
$y= "SELECT ('PRV_IDX')
FROM LLS_PRIVILEGES
WHERE `PRV_NAME` = 'Reader';";
mysql_query($y);
$x= "SELECT ('USER_IDX')
FROM LLS_USERS
WHERE `USR_LOGIN` = '".$_SESSION['tool_user']."';";
mysql_query($x);
$w= "INSERT INTO LLS_USERS_PRIVILEGES
(USP_USR_IDX,USP_PRV_IDX)
VALUES ($x,$y); ";
mysql_query($w);
我想将select语句中的这些值插入到最终表中。但是,我不确定我的语法是否正确,我无法在线找到解决方案。我不确定你是否每次都必须使用mysql_query使select语句实际占用并将其放在$变量中。
抱歉,我是SQL的新手,但是谢谢你的帮助!
答案 0 :(得分:-1)
mysql _ * 函数已弃用。请改用 PDO :
$y=$dbh->query("SELECT ('PRV_IDX')
FROM LLS_PRIVILEGES
WHERE `PRV_NAME` = 'Reader'");
$x=$dbh->prepare("SELECT ('USER_IDX')
FROM LLS_USERS
WHERE `USR_LOGIN` = ?");
$x->execute(array($_SESSION['tool_user']));
$w=$dbh->prepare("INSERT INTO LLS_USERS_PRIVILEGES
(USP_USR_IDX,USP_PRV_IDX)
VALUES (?,?)");
$y="SELECT ('PRV_IDX')
FROM LLS_PRIVILEGES
WHERE `PRV_NAME` = 'Reader'";
$x="SELECT ('USER_IDX')
FROM LLS_USERS
WHERE `USR_LOGIN` = '".$_SESSION['tool_user']."'");
$w->execute(array($x,$y));
有关 PDO 的更多信息:http://www.php.net/manual/en/book.pdo.php