Question

一个程序，让用户猜出程序选择的号码作为幸运号码。它使用一个for循环和大量的if语句。问题是我的代码在2次尝试后停止，但是假设给用户3次尝试。以下是我到目前为止的情况：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
    int iSecret, iGuess;
    srand(time(NULL));
    iSecret = rand() % 20 + 1;
    int tries = 0;

    printf("\nWelcome to the number guessing game!\nFor each game, you have at most 3 chances to guess a secret number from 1 to 20.\n");

    for (tries = 0; tries < 3 || iSecret == iGuess; tries++)
    {
        printf("Please, enter a number between 1 and 20!   ");
        scanf("%d", &iGuess);

        if (iGuess == iSecret)
        {
            printf("\nCongratulations! You won!");
            return 0;
        }

        else if (iGuess > iSecret)
        {
            tries++;
            printf("\nYour guess was too high.\n");
        }

        else if (iGuess < iSecret)
        {
            tries++;
            printf("\nYour guess was too low.\n");
        }
        if (tries == 3)
            break;
    }

    printf("\nYou have reached your third trials. The correct number is %d.\n",
            iSecret);
    return 0;
}

Answer 1

您正在递增tries两次：一次在for定义中，以及稍后在循环体中。

删除额外的tries++语句。

Answer 2

您可以在代码内部以及for语句中增加尝试次数。去掉if-blocks中的tries ++语句。

Answer 3

在循环执行期间，您多次递增变量tries，每次转弯，每次你没有猜到你的秘密

Answer 4

for循环已经递增尝试..你不需要在if语句
你不需要||因为你已经在if语句

这是固定代码：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main ()
{
  int iSecret, iGuess;
  srand ( time(NULL) );
  iSecret = rand() % 20 + 1;
  int tries = 0;

  printf("\nWelcome to the number guessing game!\nFor each game, you have at most 3 chances to guess a secret number from 1 to 20.\n");


  for (tries = 0; tries < 3 ; tries++) {

      printf ("Please, enter a number between 1 and 20!   ");
      scanf ("%d", &iGuess);

      if(iGuess == iSecret){
      printf ("\nCongratulations! You won!");
      return 0;
      }

        else if (iGuess > iSecret){
        printf ("\nYour guess was too high.\n");
        }

        else if (iGuess < iSecret){
            printf ("\nYour guess was too low.\n");
                  }

  }
  printf ("\nYou have reached your third trials. The correct number is %d.\n", iSecret);

  return 0;
  }

<强>输出：

$ ./test

Welcome to the number guessing game!
For each game, you have at most 3 chances to guess a secret number from 1 to 20.
Please, enter a number between 1 and 20!   2

Your guess was too low.
Please, enter a number between 1 and 20!   3

Your guess was too low.
Please, enter a number between 1 and 20!   4

Your guess was too low.

You have reached your third trials. The correct number is 10.

Answer 5

除了递增尝试次数太多，代码过于复杂，你可以简化逻辑，如

int main ()
{
  int iSecret, iGuess;
  srand ( time(NULL) );
  iSecret = rand() % 20 + 1;
  int tries = 0;

  printf("\nWelcome to the number guessing game!\nFor each game, you have at most 3 chances to guess a secret number from 1 to 20.\n");


  for (tries = 0; tries < 3; tries++) {
      printf ("Please, enter a number between 1 and 20!   ");
      scanf ("%d", &iGuess);

      if(iGuess == iSecret) {
        printf ("\nCongratulations! You won!");
        return 0;
      }

      printf ( "\nYour guess was too %s.\n", iGuess>iSecret?"high":"low");

  }
  printf ("\nYou have reached your third trials. The correct number is %d.\n", iSecret);
  return 0;
  }

对于C中的循环猜测游戏

5 个答案: