Question

我有一个数组：

array = ["one", "two", "two", "three"]

现在我需要创建一个单独的数组，其中包含每个项目的百分比。

最终结果：

percentages_array = [".25",".50",".50",".25]

我可以这样做：

percentage_array = []
one_count = array.grep(/one/).count
two_count = array.grep(/two/).count

array.each do |x|
  if x == "one"
    percentage_array << one_count.to_f / array.count.to_f
  elsif x == "two"
    ....
  end
end

但是我怎么能把它写得更简洁和动态呢？

Answer 1

我会按功能使用该组：

 my_array = ["one", "two", "two", "three"]
 percentages = Hash[array.group_by{|x|x}.map{|x, y| [x, 1.0*y.size/my_array.size]}]
 p  percentages #=> {"one"=>0.25, "two"=>0.5, "three"=>0.25}
 final = array.map{|x| percentages[x]}
 p final #=> [0.25, 0.5, 0.5, 0.25]

备选方案2没有group_by：

array, result = ["one", "two", "two", "three"], Hash.new
array.uniq.each  do |number|
  result[number] = array.count(number)
end
p array.map{|x| 1.0*result[x]/array.size}  #=> [0.25, 0.5, 0.5, 0.25]

Answer 2

您可以这样做，但您发现仅使用哈希h：

更有用

array = ["one", "two", "two", "three"]

fac = 1.0/array.size
h = array.reduce(Hash.new(0)) {|h, e| h[e] += fac; h}
  # => {"one"=>0.25, "two"=>0.5, "three"=>0.25} 
array.map {|e| h[e]} #  => [0.25, 0.5, 0.5, 0.25]

编辑：正如@Victor建议的那样，最后两行可以替换为：

array.reduce(Hash.new(0)) {|h, e| h[e] += fac; h}.values_at(*array)

谢谢，Victor，一个明确的改进（除非使用哈希就足够了）。

Answer 3

percentage_array = []
percents = [0.0, 0.0, 0.0]
array.each do |x|
  number = find_number(x)
  percents[number] += 1.0 / array.length
end
array.each do |x|
  percentage_array.append(percents[find_number(x)].to_s)
end

def find_number(x)
  if x == "two"
    return 1
  elsif x == "three"
    return 2
  end
  return 0
end

Answer 4

这是一种通用的方法：

def percents(arr)
  map = Hash.new(0)
  arr.each { |val| map[val] += 1 }
  arr.map { |val| (map[val]/arr.count.to_f).to_s }
end

p percents(["one", "two", "two", "three"]) # prints ["0.25", "0.5", "0.5", "0.25"]

Ruby计算数组对象的百分比

4 个答案: