Question

编译时没有错误......但是我的输出没有任何结果。我知道这是一个非常愚蠢的编码尝试...我大多数都在使用数字......字符串的东西让我感到困惑。

#include <iostream>
#include <string>

using namespace std;
char chr;

int main()
{
    string name;
    string artist;
    string Taylor;
    string Alan;
    string general;
    string box;
    string seating;

    cout << "Enter your name followed by the return key" << endl;
    cin >> name;
    cout << endl;
    cout << "Enter Taylor for Taylor Swift tickets or Alan for Alan Jacskon seats, followed" << endl << "by the enter key" << endl << endl;
    cout << "Enter box for box seating or general for general seating, followed by the enter key" << endl << endl;
    cin >> artist;
    cin >> seating;

    if ( artist + seating == Taylor + general )
        cout <<  name << ", Your ticket will cost $60" << endl;
    else if ( artist + seating == Taylor + box )
        cout <<  name << ", Your ticket will cost $100" << endl;
    else if ( artist + seating == Alan + box )
        cout <<  name << ", Your ticket will cost $75" << endl;
    else if ( artist + seating == Alan + general )
        cout <<  name << ", Your ticket will cost $50" << endl;

    cin >> chr;
    return 0;
}

Answer 1

Taylor，Alan，general和box在您的逻辑文字值中，而不是变量......您的代码应该成为

string Taylor = "Taylor";
string Alan = "Alan";
string general = "general";
string box = "box";

在C ++中，你不能只写

if ( artist + seating == "Taylor" + "general" )

由于原因太复杂而无法解释，您可以改为删除这些值的变量并使用

if ( artist + seating == "Taylorgeneral" )

BTW：我不确定C ++是否是学习编程的好选择。在我看来，更适合这项工作Python（或者用汇编程序编写6502之类的简单CPU，但这是另一种完全不同的方法）。

Answer 2

字符串Taylor, Alan, general, box永远不会被初始化。比较它们毫无意义。你可能想要的是：

string Taylor = "Taylor";
string Alan = "Alan";
string general = "general";
string box = "box";

Answer 3

当我将if语句更改为此格式时，它们起作用了。

if（（artist ==“Taylor”）＆amp;＆amp;（seat ==“general”））

  cout <<  name << ", Your ticket will cost $60" << endl;

Answer 4

你还没有初始化字符串泰勒;艾伦;一般的;弦盒;所以它们都是''\ 0'，它不匹配任何情况，所以你得不到输出。什么，更多当你使用cin进行输入时，它会忽略'\ n'，''，你也可以使用cin.getline（string a）作为输入

简单嵌套“If else”语句

4 个答案: