function handleFileSelect(evt) {
var files = evt.target.files;
for (var i = 0, f; i<2 ; i++){
f = files[i]
if (!f.type.match('image.*')) {
continue;
}
var reader = new FileReader();
reader.onload = (function(theFile){
return function(e) {
var span = document.createElement('span');
span.innerHTML = ['<img class="thumb" src="', e.target.result,'" title="',escape(theFile.name), '"/>'].join('');
document.getElementById('pic'+i).insertBefore(span, null);
};
})(f,i);
reader.readAsDataURL(f);
}
}
我有HERE, EXAMPLE 3的这个脚本,我试图将每个文件放在不同的位置。
<tr><td colspan="2"><input type="file" id="inputFilesID" multiple ></td></tr>
<tr><td>Front</td><td><output id="pic0" /></td></tr>
<tr><td>Back</td><td><output id="pic1" /></td></tr>
例如,如果那是我的html,为什么如果我把2个图像我的脚本试图把所有内容放在:
<tr><td>Bottom</td><td><output id="pic2" /></td></tr>
答案 0 :(得分:0)
// Scripts.js中的逻辑
var canvas = document.getElementById('our-canvas'),
context = canvas.getContext('2d');
uploadedFile = document.getElementById('uploaded-file');
window.addEventListener('DOMContentLoaded',initImageLoader) ;
function initImageLoader(){
uploadedFile.addEventListener('change',handleManualUploadedFiles);
function handleManualUploadedFiles(ev){
var file = ev.target.files[0];
handleFile(file);
}
}
function handleFile(file){
var ImageType = /image.*/;
if(file.type.match(ImageType)){
var reader = new FileReader();
reader.onloadend = function(event){
var tempImageStore = new Image();
tempImageStore.onload = function(ev){
canvas.height = ev.target.height;
canvas.width = ev.target.width;
context.drawImage(ev.target,0,0);
}
tempImageStore.src = event.target.result;
}
reader.readAsDataURL(file);
}
}
//以HTML格式显示
<b>our image canvas </b>
<input type="file" id="uploaded-file" />
<canvas id= "our-canvas" class="image-container"> </canvas>
<script src="scripts.js" > </script>
答案 1 :(得分:0)
use npm jimp
============================
Jimp.read('./path/to/image.jpg')
.then(image => {
console.log(image.bitmap)//having the image buffer data,width,height ...etc
// Do stuff with the image.
})
.catch(err => {
// Handle an exception.
});