在我的Android应用程序中,我必须允许用户单击按钮以打开图库并选择图像。然后需要将特定的选定图像加载到我的布局(UI)中的图像视图中。我有一些代码,但它来自java.lang.outofmemory.Please任何人都可以帮助我?
答案 0 :(得分:3)
您应该在onActivityResult()方法上解码图像uri。 将此方法称为decodeBitmap。
/**
* This is very useful to overcome Memory waring issue while selecting image
* from Gallery
*
* @param selectedImage
* @param context
* @return Bitmap
* @throws FileNotFoundException
*/
public static Bitmap decodeBitmap(Uri selectedImage, Context context)
throws FileNotFoundException {
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeStream(context.getContentResolver()
.openInputStream(selectedImage), null, o);
final int REQUIRED_SIZE = 100;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE || height_tmp / 2 < REQUIRED_SIZE) {
break;
}
width_tmp /= 2;
height_tmp /= 2;
scale *= 2;
}
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
return BitmapFactory.decodeStream(context.getContentResolver()
.openInputStream(selectedImage), null, o2);
}
有关详细信息,请参阅主题有效显示位图
http://developer.android.com/training/displaying-bitmaps/index.html
希望得到这个帮助。
答案 1 :(得分:0)
在这里,您将了解为什么会出现此异常以及如何正确显示位图:http://developer.android.com/training/displaying-bitmaps/index.html