Question

我曾经依赖Mockito直到今天我有一些静态方法的最终类，所以我要切换到JMockit。我之前对此一无所知，所以问题是：如何将Mockito中的类似逻辑应用到JMockit？

public final class ServiceData extends BaseData {

    private List<Data> data;

    public ServiceData(List<Data> data) {
         this.data = data;
         // something else
    }

    public static Container getContainer() {
         return super.getContainer();
    }

    public Data getDataAt(Index index) {
         return super.getContainer().get(index);
    }

}

用Mockito写的测试看起来像：

@Test
public void test() {
    ServiceData mockServiceData = mock(ServiceData.class);
    Data mockData = mock(Data.class);
    // only stubbing some of the methods
    Container mockContainer = spy(Container.class);
    doReturn(something).when(mockContainer.someMethod());
    when(mockServiceData.getContainer()).thenReturn(mockContainer);
    when(mockServiceData.getDataAt(any(Index.class)).thenReturn(mockData);

    // some assertions
}

这不起作用，因为Mockito不能模拟最终类和静态方法（getContainer）那么如何在JMockit中编写相同的逻辑呢？感谢。

Answer 1

以下是示例测试的JMockit等效项：

@Test
public void test(
    @Mocked final ServiceData mockServiceData, @Mocked final Data mockData,
    @Mocked final Container mockContainer)
{
    // only stubbing some of the methods
    new Expectations(mockContainer) {{
        mockContainer.someMethod(); result = "something";
        mockServiceData.getContainer(); result = mockContainer;
        mockServiceData.getDataAt((Index) any); result = mockData;
    }};

    // some assertions
}

要模拟static方法，语法是相同的，只是你会写ServiceData.getContainer(); result = mockContainer;。

从Mockito切换到JMockit

1 个答案: