Question

我已经完成了这个C ++数据结构程序大部分是正确的，但我遇到了RefFunction()参数的问题。它们设计得不是很合适。它们不应该通过价值传递，而是通过引用传递，我不知道该怎么做。它需要引用int和对double的引用。它查询用户输入要存储在其参数引用的变量中的值。然后能够返回类实例并在main()中打印值。我非常感谢任何帮助，因为我很困难。非常感谢你。

标题文件：

#ifndef Prog1Class_h
#define Prog1Class_h


//A data structure of type Prog1Struct containing three variables
struct Prog1Struct
{
    int m_iVal;
    double m_dVal;
    char m_sLine[81];
};

// A class, Prog1Class, containing a constructor and destructor
// and function prototypes
class Prog1Class
{
public:
    Prog1Class(); 
    ~Prog1Class(); 

    void PtrFunction(int *, double *);
    void RefFunction(int, double);
    void StructFunction(Prog1Struct *);
};

#endif

.CPP文件

#include "Prog1Class.h"
#include <string>
#include <iostream>
using namespace std;

Prog1Class::Prog1Class() {}
Prog1Class::~Prog1Class() {}

// PtrFunction shall query the user to input values to be stored in the
// variables referenced by it's pointer arguments
void Prog1Class::PtrFunction(int *a, double *b)
{
    cout << "Input keyboard values of type integer and double"<<endl; 
    cin>>*a >>*b;
}

// RefFunction shall be a C++ Reference function and shall query the user to
// input values to be stored in the variables referenced by it's arguments
void Prog1Class::RefFunction(int a, double b)
{
    cout << "Input keyboard values of type integer and double"<<endl;
    cin >>a >>b;
}

// StructFunction shall query the user to input values to be stored in the
// three fields of the data structure referenced by its argument
void Prog1Class::StructFunction(Prog1Struct* s)
{
    cout << "Input keyboard values of type integer and double"<<endl; 
    cin >>s->m_iVal>>s->m_dVal;
    cout <<"Input a character string";
    cin.ignore(1000, '\n');
    cin.getline(s->m_sLine, 81, '\n'); 
}

Answer 1

在C ++中，您不需要使用指针来通过引用传递。

声明这样的函数：

void Prog1Class::RefFunction(int& a, double& b)

您对RefFunction内的a和b所做的更改将反映在原始变量

中

C ++数据结构编程：通过引用传递值？

1 个答案: