Question

我的应用程序中有以下结构：

|
|----user folder
|        |
|        |-----Member.php
|        | 
|        |---- tests Folder
|                  |
|                  |-----Member.php

以下是用户文件夹中的Member.php：

<?php

namespace user;

class Member
{
    private $firstName;
    private $lastName;
    private $email;
    private $password;
    private $cell;

    public function __construct()
    {

    }

    public function getFirstName()
    {
        return $this->firstName;
    }

    public function setFirstName($firstName)
    {
        $this->firstName = $firstName;
        return TRUE;
    }

    public function getLastName()
    {
        return $this->lastName;
    }

    public function setLastName($lastName)
    {
        $this->lastName = $lastName;
        return TRUE;
    }

    public function getEmail()
    {
        return $this->email;
    }

    public function setEmail($email)
    {
        $this->email = $email;
        return TRUE;
    }

    public function getPassword()
    {
        return $this->password;
    }

    public function setPassword($password)
    {
        $this->password = $password;
        return TRUE;
    }

    public function getCell()
    {
        return $this->cell;
    }

    public function setCell($cell)
    {
        $this->cell = $cell;
        return TRUE;
    }
}

这是我的Member.php在tests文件夹中：

<?php
/*
 * Member class getters and setters tests
 */
namespace user;
use user;

$member = new Member();
$member->setFirstName("Javad");
if($member->getFirstName() == "Javad")
    echo "Test code 1 passed";
else
    echo "Test code 1 failed";

$member = new Member();
$member->setLastName("Akbari");
if($member->getLastName() == "Akbari")
    echo "Test code 2 passed";
else
    echo "Test code 2 failed";

$member = new Member();
$member->setEmail("j2omrani@gmail.com");
if($member->getEmail() == "j2omrani@gmail.com")
    echo "Test code 3 passed";
else
    echo "Test code 3 failed";

$member = new Member();
$member->setPassword("123456");
if($member->getPassword() == "123456")
    echo "Test code 4 passed";
else
    echo "Test code 4 failed";

$member = new Member();
$member->setCell("09121234567");
if($member->getCell() == "09121234567")
    echo "Test code 5 passed";
else
    echo "Test code 5 failed";

当我想创建一个Object时，它抛出异常并说：

Fatal error: Class 'user\Member' not found in C:\xampp\htdocs\auto24\user\tests\Member.php on line 8

我的问题是如何使用命名空间调用测试文件夹文件中的成员对象？

Answer 1

您无法导入命名空间（import user）。您需要导入具体类（use user\Member）
无需导入Member，因为它位于同一名称空间
use语句不包含文件。你必须考虑某种自动加载。考虑PSR-0和/或Composer

要解决您的问题 ad hoc ，请使用include：

include '../Member.php';

Answer 2

您需要包含命名空间和类名：use user\Member;

<强> Member.php：

namespace user;
class Member
{
    private $firstName;
    private $lastName;
    private $email;
    private $password;
    private $cell;
    //and some other stuff
}

测试文件夹中的Member.php：

namespace user\tests\user;
use user\Member;

$member = new Member();

我假设您还需要将以下内容添加到测试文件夹中的Member.php，如果您还没有：

include '../Member.php';

或者，您也可以使用自动加载器动态加载类/命名空间。

PHP自动加载课程：http://www.php.net/manual/en/function.spl-autoload-register.php

困惑于php命名空间

2 个答案: