我正在使用CodeIgniter文件上传类。
我无法将错误数组加载到文件上载表单视图中。 (这会返回'未定义的变量:错误'消息,或'数组到字符串转换'错误消息)
我也无法将upload_data数组加载到成功视图中。 (这会返回'数组到字符串转换'错误'消息。)
这是我的控制器 - upload.php
<?php
class Upload extends Admin_Controller {
function __construct()
{
parent::__construct();
$this->load->helper(array('form', 'url'));
$this->load->helper('directory');
}
function index()
{
$this->data['subview'] = 'admin/upload_form';
$this->load->view('admin/_layout_main', $this->data);
}
function do_upload()
{
$this->load->library('upload');
if ( ! $this->upload->do_upload())
{
$error = array('error' => $this->upload->display_errors());
$this->data['error'] = $error;
$this->data['subview'] = 'admin/upload_form';
$this->load->view('admin/_layout_main', $this->data);
}
else
{
$upload_data = array('upload_data' => $this->upload->data());
$this->data['upload_data'] = $upload_data;
$this->data['subview'] = 'admin/upload_success' ;
$this->load->view('admin/_layout_main', $this->data);
}
}
}
?>
这是上传表单视图upload_form.php
<?php echo $error;?>
<?php echo form_open_multipart('admin/upload/do_upload');?>
<input type="file" name="userfile" size="20" />
<br /><br />
<input type="submit" value="upload" />
</form>
这是成功的页面视图
<ul>
<?php foreach ($upload_data as $item => $value):?>
<li><?php echo $item;?>: <?php echo $value;?></li>
<?php endforeach; ?>
</ul>
<p><?php echo anchor('admin/upload', 'Upload Another File!'); ?></p>
答案 0 :(得分:1)
$upload_data = array('upload_data' => $this->upload->data());
$this->data['upload_data'] = $upload_data;
这意味着当你在视图中print_r $ upload_data时,其中有一个数组,其中一个键为“upload_data”,另一个数组为值。然后,当你回显$ value时,它会返回一个错误,因为它是一个数组而不是一个字符串。
我相信你所寻找的只是:
$this->data['upload_data'] = $this->upload->data();